DOC PREVIEW
Berkeley COMPSCI 61C - Lecture Notes

This preview shows page 1-2-23-24 out of 24 pages.

Save
View full document
View full document
Premium Document
Do you want full access? Go Premium and unlock all 24 pages.
Access to all documents
Download any document
Ad free experience
View full document
Premium Document
Do you want full access? Go Premium and unlock all 24 pages.
Access to all documents
Download any document
Ad free experience
View full document
Premium Document
Do you want full access? Go Premium and unlock all 24 pages.
Access to all documents
Download any document
Ad free experience
View full document
Premium Document
Do you want full access? Go Premium and unlock all 24 pages.
Access to all documents
Download any document
Ad free experience
Premium Document
Do you want full access? Go Premium and unlock all 24 pages.
Access to all documents
Download any document
Ad free experience

Unformatted text preview:

PowerPoint PresentationAdministriviaExample: The C Switch Statement (3/3)C functionsFunction Call BookkeepingInstruction Support for Functions (1/6)Instruction Support for Functions (2/6)Instruction Support for Functions (3/6)Instruction Support for Functions (4/6)Instruction Support for Functions (5/6)Instruction Support for Functions (6/6)Nested Procedures (1/2)Nested Procedures (2/2)C memory Allocation reviewUsing the Stack (1/2)Using the Stack (2/2)Steps for Making a Procedure CallRules for ProceduresBasic Structure of a FunctionMIPS RegistersOther RegistersPeer InstructionSlide 24“And in Conclusion…”CS61C L11 Introduction to MIPS: Procedures I (1)Garcia © UCBLecturer PSOE Dan Garciawww.cs.berkeley.edu/~ddgarciainst.eecs.berkeley.edu/~cs61c CS61C : Machine Structures Lecture 11 – Introduction to MIPS Procedures I Smart crumble w/pressure A study showed that studentswith a “high working-memory [short-term] (HWM) capacity” (prob. most Cal students) crack under pressure, but LWM students didn’t. Under pressure, HWM = LWM. www.livescience.com/humanbiology/050209_under_pressure.htmlCS61C L11 Introduction to MIPS: Procedures I (2)Garcia © UCBAdministrivia•High-pressure midterm evaluations :-)•Review-Sun, 2005-03-06, 2pm @ 10 Evans•Midterm-Mon, 2005-03-07, 7-10pm @ 1 Le Conte•Dan’s before-class graphics videos: www.siggraph.org/publications/video-review/SVR.html•Project 1 out (make sure to work on it this weekend), due next Friday•An easy HW4 will follow, due Wed afterCS61C L11 Introduction to MIPS: Procedures I (4)Garcia © UCBExample: The C Switch Statement (3/3)•Final compiled MIPS code: bne $s5,$0,L1 # branch k!=0 add $s0,$s3,$s4 #k==0 so f=i+j j Exit # end of case so ExitL1: addi $t0,$s5,-1 # $t0=k-1 bne $t0,$0,L2 # branch k!=1 add $s0,$s1,$s2 #k==1 so f=g+h j Exit # end of case so ExitL2: addi $t0,$s5,-2 # $t0=k-2 bne $t0,$0,L3 # branch k!=2 sub $s0,$s1,$s2 #k==2 so f=g-h j Exit # end of case so ExitL3: addi $t0,$s5,-3 # $t0=k-3 bne $t0,$0,Exit # branch k!=3 sub $s0,$s3,$s4 #k==3 so f=i-j Exit:Removing breaks does NOT translate to removing jumps in this code… (my bad)CS61C L11 Introduction to MIPS: Procedures I (5)Garcia © UCBC functionsmain() {int i,j,k,m;...i = mult(j,k); ... m = mult(i,i); ...}/* really dumb mult function */int mult (int mcand, int mlier){int product; product = 0;while (mlier > 0) { product = product + mcand; mlier = mlier -1; }return product;}What information mustcompiler/programmer keep track of?What instructions can accomplish this?CS61C L11 Introduction to MIPS: Procedures I (6)Garcia © UCBFunction Call Bookkeeping•Registers play a major role in keeping track of information for function calls.•Register conventions:•Return address $ra•Arguments $a0, $a1, $a2, $a3•Return value $v0, $v1•Local variables $s0, $s1, … , $s7•The stack is also used; more later.CS61C L11 Introduction to MIPS: Procedures I (7)Garcia © UCBInstruction Support for Functions (1/6) ... sum(a,b);... /* a,b:$s0,$s1 */}int sum(int x, int y) {return x+y;} address1000 1004 1008 1012 1016 2000 2004CMIPSIn MIPS, all instructions are 4 bytes, and stored in memory just like data. So here we show the addresses of where the programs are stored.CS61C L11 Introduction to MIPS: Procedures I (8)Garcia © UCBInstruction Support for Functions (2/6) ... sum(a,b);... /* a,b:$s0,$s1 */}int sum(int x, int y) {return x+y;} address1000 add $a0,$s0,$zero # x = a1004 add $a1,$s1,$zero # y = b 1008 addi $ra,$zero,1016 #$ra=10161012 j sum #jump to sum1016 ...2000 sum: add $v0,$a0,$a12004 jr $ra # new instructionCMIPSCS61C L11 Introduction to MIPS: Procedures I (9)Garcia © UCBInstruction Support for Functions (3/6) ... sum(a,b);... /* a,b:$s0,$s1 */}int sum(int x, int y) {return x+y;} 2000 sum: add $v0,$a0,$a12004 jr $ra # new instructionCMIPS•Question: Why use jr here? Why not simply use j?•Answer: sum might be called by many functions, so we can’t return to a fixed place. The calling proc to sum must be able to say “return here” somehow.CS61C L11 Introduction to MIPS: Procedures I (10)Garcia © UCBInstruction Support for Functions (4/6)•Single instruction to jump and save return address: jump and link (jal)•Before:1008 addi $ra,$zero,1016 #$ra=10161012 j sum #goto sum•After:1008 jal sum # $ra=1012,goto sum•Why have a jal? Make the common case fast: function calls are very common. Also, you don’t have to know where the code is loaded into memory with jal.CS61C L11 Introduction to MIPS: Procedures I (11)Garcia © UCBInstruction Support for Functions (5/6)•Syntax for jal (jump and link) is same as for j (jump):jal label• jal should really be called laj for “link and jump”:•Step 1 (link): Save address of next instruction into $ra (Why next instruction? Why not current one?)•Step 2 (jump): Jump to the given labelCS61C L11 Introduction to MIPS: Procedures I (12)Garcia © UCBInstruction Support for Functions (6/6)•Syntax for jr (jump register):jr register•Instead of providing a label to jump to, the jr instruction provides a register which contains an address to jump to.•Only useful if we know exact address to jump to.•Very useful for function calls:•jal stores return address in register ($ra)•jr $ra jumps back to that addressCS61C L11 Introduction to MIPS: Procedures I (13)Garcia © UCBNested Procedures (1/2)int sumSquare(int x, int y) {return mult(x,x)+ y;}•Something called sumSquare, now sumSquare is calling mult.•So there’s a value in $ra that sumSquare wants to jump back to, but this will be overwritten by the call to mult.•Need to save sumSquare return address before call to mult.CS61C L11 Introduction to MIPS: Procedures I (14)Garcia © UCBNested Procedures (2/2)•In general, may need to save some other info in addition to $ra.•When a C program is run, there are 3 important memory areas allocated:•Static: Variables declared once per program, cease to exist only after execution completes. E.g., C globals•Heap: Variables declared dynamically•Stack: Space to be used by procedure during execution; this is where we can save register valuesCS61C L11 Introduction to MIPS: Procedures I (15)Garcia © UCBC memory Allocation review0AddressCodeProgramStaticVariables declaredonce per programHeapExplicitly created space, e.g., malloc(); C pointersStackSpace for saved procedure information$sp


View Full Document

Berkeley COMPSCI 61C - Lecture Notes

Documents in this Course
SIMD II

SIMD II

8 pages

Midterm

Midterm

7 pages

Lecture 7

Lecture 7

31 pages

Caches

Caches

7 pages

Lecture 9

Lecture 9

24 pages

Lecture 1

Lecture 1

28 pages

Lecture 2

Lecture 2

25 pages

VM II

VM II

4 pages

Midterm

Midterm

10 pages

Load more
Download Lecture Notes
Our administrator received your request to download this document. We will send you the file to your email shortly.
Loading Unlocking...
Login

Join to view Lecture Notes and access 3M+ class-specific study document.

or
We will never post anything without your permission.
Don't have an account?
Sign Up

Join to view Lecture Notes 2 2 and access 3M+ class-specific study document.

or

By creating an account you agree to our Privacy Policy and Terms Of Use

Already a member?