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Berkeley ELENG 105 - CMOS Amplifiers

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EE105 - Spring 2007Microelectronic Devices and CircuitsLecture 6CMOS Amplifiers2CMOS Amplifiers General Considerations Common-Source Stage Common-Gate Stage Source Follower Summary and Additional Examples3Lecture Outline4Voltage Amplifier In an ideal voltage amplifier, the input impedance is infinite and the output impedance zero. But in reality, input or output impedances depart from their ideal values.5Input / Output Impedances The figure above shows the techniques of measuring input and output impedances.xxxVRi=6Common-Source StageDDoxnvDmvRILWCARgAμλ20−=−==7Operation in Saturation In order to maintain operation in saturation, Voutcannot fall below Vinby more than one threshold voltage.  The condition above ensures operation in saturation. ()1Condition for M in saturation out in THDD D D GS THVVVVRIVV>−⇒− >−8CS Stage with λ=0LoutinLmvRRRRgA=∞=−=9CS Stage with λ≠0 However, channel length modulation leads to finite output resistance, ro, which is in parallel with the load resistance, RL()OLoutinOLmvrRRRrRgA||||=∞=−=10CS Gain Variation with Channel Length Since λ is inversely proportional to L, the intrinsic voltage gain actually becomes proportional to the square root of L. DoxnDoxnvIWLCILWCAμλμ22∝=11MOS Biasing()()11222211112112,212 unknows ( ), 2 equationsDD GS D SDnoxGSTHGS DDDGS TH THnox SRVVIRRRWICVVLVIRVVVVVV VRRVWCRLμμ=++=−⇒⎛⎞=− − + + −⎜⎟+⎝⎠= Voltage at X is determined by VDD, R1, and R2. VGScan be found using the equation above, and IDcan be found by using the NMOS current equation.12Self-Biased MOS Stage The circuit above is analyzed by noting M1is in saturation and no potential drop appears across RG.()212D D GS S D DDDnoxGSTHIR V RI VWICVVLμ++ ==−13Current Sources When in saturation region, a MOSFET behaves as a current source. NMOS draws current from a point to ground (sinks current), whereas PMOS draws current from VDDto a point (sources current).14CS Stage with Current-Source Load To alleviate the headroom problem, an active current-source load is used. This is advantageous because a current-source has a high output resistance and can tolerate a small voltage drop across it. ()21211||||OOoutOOmvrrRrrgA=−=15PMOS CS Stage with NMOS as Load  Similarly, with PMOS as input stage and NMOS as the load, the voltage gain is the same as before.21 2(||)vmOOAgrr=−16CS Stage with Diode-Connected Load Lower gain, but less dependent on process parameters.()()121211221|| ||/1/ vm OOmvmmAg rrgWLAggWL⎛⎞=−⎜⎟⎝⎠=− ⋅ =−17CS Stage with Diode-Connected PMOS Device Note that PMOS circuit symbol is usually drawn with the source on top of the drain.⎟⎟⎠⎞⎜⎜⎝⎛−=2112||||1oommvrrggA18CS Stage with Degeneration Similar to bipolar counterpart, when a CS stage is degenerated, its gain, I/O impedances, and linearity change.10DvSmRARgλ=−+=19Example of CS Stage with Degeneration A diode-connected device degenerates a CS stage.1211DvmmRAgg=−+20CS Stage with Gate Resistance Since at low frequencies, the gate conducts no current, gate resistance does not affect the gain or I/O impedances.0GRV =21Output Impedance of CS Stage with Degeneration Similar to the bipolar counterpart, degeneration boosts output impedance.out m O S OrgrRr≈+22Output Impedance Example (I) When 1/gmis parallel with rO2, we often just consider 1/gm1122111out O mmmRr ggg⎛⎞=+ +⎜⎟⎝⎠23Output Impedance Example (II) In this example, the impedance that degenerates the CS stage is rO, instead of 1/gmin the previous example. 112 1out m O O ORgrr r≈+24CS Core with Biasing Degeneration is used to stabilize bias point, and a bypass capacitor can be used to obtain a larger small-signal voltage gain at the frequency of interest. 1212||,1|| DvvmDGSmRR RAAgRRRRRg−=⋅ =−++25Common-Gate Stage Common-gate stage is similar to common-base stage: a rise in input causes a rise in output. So the gain is positive. vmDAgR=26Signal Levels in CG Stage In order to maintain M1 in saturation, the signal swing at Voutcannot fall below Vb-VTH27I/O Impedances of CG Stage The input and output impedances of CG stage are similar to those of CB stage.out DRR=1inmRg=0λ=28CG Stage with Source Resistance When a source resistance is present, the voltage gain is equal to that of a CS stage with degeneration, only positive.1DvSmRARg=+29Generalized CG Behavior When a gate resistance is present it does not affect the gain and I/O impedances since there is no potential drop across it (at low frequencies). The output impedance of a CG stage with source resistance is identical to that of CS stage with degeneration.()1out m O S ORgrRr=+ +30Example of CG Stage Diode-connected M2 acts as a resistor to provide the bias current.()1121out m Din m m SvgRvggR=++11 121|| ||out m O S O DmRgr RrRg⎡⎤⎛⎞≈+⎢⎥⎜⎟⎢⎥⎝⎠⎣⎦31CG Stage with Biasing R1and R2provide gate bias voltage, and R3provides a path for DC bias current of M1to flow to ground. ()()33|| 1/|| 1/moutmDin m SRgvgRvR gR=⋅+32Source Follower Stage1vA <33Source Follower Core Similar to the emitter follower, the source follower can be analyzed as a resistor divider. ||1||out O LinOLmvrRvrRg=+34Source Follower Example In this example, M2acts as a current source.12121||1||OOvOOmrrArrg=+35Output Resistance of Source Follower The output impedance of a source follower is relatively low, whereas the input impedance is infinite (at low frequencies); thus, a good candidate as a buffer.11|| || ||out O L LmmRrR Rgg=≈36Source Follower with Biasing RGsets the gate voltage to VDD, whereas RSsets the drain current The quadratic equation above can be solved for ID()212DnoxDDDSTHWICVIRVLμ=−−37Supply-Independent Biasing If Rsis replaced by a current source, drain current IDbecomes independent of supply voltage. 38Example of a CS Stage (I) M1 acts as the input device and M2, M3 as the load.1123312331|| || ||1|| || ||vm OOOmout O O OmAgrrrgRrrrg⎛⎞=−⎜⎟⎝⎠=39Example of a CS Stage (II) M1acts as the input device, M3as the source resistance, and M2as the load. 231311||OvOmmrArgg=−+40Examples of CS and CG Stages With the input connected to different locations, the two circuits, although identical in other aspects, behave differently.2_1OvCGSmrARg=+[]_21111(1 ) ||vCS m m O S O OAggrRrr=− + +41Example of a Composite Stage (I) By


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Berkeley ELENG 105 - CMOS Amplifiers

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