Fall 2009 EE40 Homework 2 Due September 17 Thursday 12 00 noon in Cory 240 Reading Assignments Chapter 2 of Hambley textbook Chapter 14 1 14 2 and 14 3 of Hambley textbook Problem 1 Mesh Analysis Hambley P2 62 Solve for the power delivered by the voltage source in Figure P2 62 below using the mesh current method Problem 2 Thevenin Equivalent Circuit Hambley P 2 82 If we measure the voltage at the terminals of a two terminal network with two known and different resistive loads we can determine the Th venin and Norton equivalent circuits When a 7 load is attached to a two terminal circuit the load voltage is 7 V When the load is increased to 10 the load voltage becomes 8 V Find the Th venin voltage and resistance for the circuit Problem 3 Th venin and Norton Equivalent Circuits Hambley P2 83 Find the Th venin and Norton equivalent circuits for the circuit shown in Figure P2 83 below Problem 4 Principle of Superposition Hambley P2 100 Use superposition to solve for i1 in the circuit of Figure P2 100 below In this case the controlled source is a voltage source so replace it with an independent voltage source before applying superposition Problem 5 Maximum power transfer Hambley P2 84 Find the maximum power that can be delivered to a resistive load by the circuit shown in Figure P2 75 below For what value of load resistance is the power maximum Problem 6 Wheatstone Bridge Hambley P2 104 Derive expressions for the Th venin voltage and resistance seen by the detector in the Wheatstone bridge in Figure 2 64 below In other words remove the detector from the circuit and determine the Th venin resistance for the remaining two terminal circuit What is the value of the Th venin voltage when the bridge is balanced Problem 7 Op amp Inverting Amplifier Hambley P14 11 Determine the closed loop voltage gain of the circuit shown in Figure P14 11 below assuming an ideal op amp Problem 8 Op Amp Noninverting Amplifier Hambley P14 20 For each of the five circuits shown in Figure P14 20 below assume that the op amp is ideal and find the value of v0 Each of the circuits has negative feedback so the summing point constraint applies
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