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CMU CS 15213 - Introduction to Computer Systems

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Introduction to Computer SystemsCourse ThemeGreat Reality #1Computer ArithmeticGreat Reality #2Assembly Code ExampleCode to Read CounterSlide 8Measuring TimeTiming System PerformanceSlide 11Great Reality #3Memory Performance ExampleMatmult Performance (Alpha 21164)Memory SystemBlocked matmult perf (Alpha 21164)Real Memory PerformanceMemory Referencing Bug ExampleMemory Referencing ErrorsGreat Reality #4Great Reality #5Hardware Organization (Naïve)Role within CurriculumCourse PerspectiveCourse Perspective (Cont.)Teaching staffTextbooksCourse ComponentsGetting HelpPolicies: AssignmentsCheatingPolicies: GradingFacilitiesPrograms and DataPerformanceThe Memory HierarchyLinking and Exceptional Control FlowVirtual memoryI/O, Networking, and ConcurrencyLab RationaleAutolab Web ServiceAcknowledgementHave a Great Semester!Introduction to Computer SystemsTopics:ThemeFive great realities of computer systemsHow this fits within CS curriculumStaff, text, and policiesLecture topics and assignmentsLab rationaleclass01.ppt15-213“The Class That Gives CMU Its Zip!”Seth Goldstein & Andreas NowatzykJanuary 13, 2004– 2 –15-213, S’04Course ThemeAbstraction is good, but don’t forget reality!Courses to date emphasize abstractionAbstract data typesAsymptotic analysisThese abstractions have limitsEspecially in the presence of bugsNeed to understand underlying implementationsUseful outcomesBecome more effective programmersAble to find and eliminate bugs efficientlyAble to tune program performancePrepare for later “systems” classes in CS & ECECompilers, Operating Systems, Networks, Computer Architecture, Embedded Systems– 3 –15-213, S’04Great Reality #1Int’s are not Integers, Float’s are not RealsExamplesIs x2 ≥ 0?Float’s: Yes!Int’s:» 40000 * 40000 --> 1600000000» 50000 * 50000 --> ??Is (x + y) + z = x + (y + z)?Unsigned & Signed Int’s: Yes!Float’s:» (1e20 + -1e20) + 3.14 --> 3.14» 1e20 + (-1e20 + 3.14) --> ??-1794967296 0– 4 –15-213, S’04Computer ArithmeticDoes not generate random valuesArithmetic operations have important mathematical propertiesCannot assume “usual” propertiesDue to finiteness of representationsInteger operations satisfy “ring” propertiesCommutativity, associativity, distributivityFloating point operations satisfy “ordering” propertiesMonotonicity, values of signsObservationNeed to understand which abstractions apply in which contextsImportant issues for compiler writers and serious application programmers– 5 –15-213, S’04Great Reality #2You’ve got to know assemblyChances are, you’ll never write program in assemblyCompilers are much better & more patient than you areUnderstanding assembly key to machine-level execution modelBehavior of programs in presence of bugsHigh-level language model breaks downTuning program performanceUnderstanding sources of program inefficiencyImplementing system softwareCompiler has machine code as targetOperating systems must manage process state– 6 –15-213, S’04Assembly Code ExampleTime Stamp CounterSpecial 64-bit register in Intel-compatible machinesIncremented every clock cycleRead with rdtsc instructionApplicationMeasure time required by procedureIn units of clock cyclesdouble t;start_counter();P();t = get_counter();printf("P required %f clock cycles\n", t);– 7 –15-213, S’04Code to Read CounterWrite small amount of assembly code using GCC’s asm facilityInserts assembly code into machine code generated by compilerstatic unsigned cyc_hi = 0;static unsigned cyc_lo = 0;/* Set *hi and *lo to the high and low order bits of the cycle counter. */void access_counter(unsigned *hi, unsigned *lo){ asm("rdtsc; movl %%edx,%0; movl %%eax,%1" : "=r" (*hi), "=r" (*lo) :: "%edx", "%eax");}– 8 –15-213, S’04Code to Read Counter/* Record the current value of the cycle counter. */void start_counter(){ access_counter(&cyc_hi, &cyc_lo);}/* Number of cycles since the last call to start_counter. */double get_counter(){ unsigned ncyc_hi, ncyc_lo; unsigned hi, lo, borrow; /* Get cycle counter */ access_counter(&ncyc_hi, &ncyc_lo); /* Do double precision subtraction */ lo = ncyc_lo - cyc_lo; borrow = lo > ncyc_lo; hi = ncyc_hi - cyc_hi - borrow; return (double) hi * (1 << 30) * 4 + lo;}– 9 –15-213, S’04Measuring TimeTrickier than it Might LookMany sources of variationExampleSum integers from 1 to n n Cycles Cycles/n100 961 9.611,000 8,407 8.411,000 8,426 8.4310,000 82,861 8.2910,000 82,876 8.291,000,000 8,419,907 8.421,000,000 8,425,181 8.431,000,000,000 8,371,2305,591 8.37– 10 –15-213, S’04main(int argc, char** argv){ ... for (i=0; i<t; i++) { start_counter(); count(n); times[i] = get_counter(); } ...}int count(int n){ int i; int sum = 0; for (i=0; i<n; i++) { sum += i; } return sum;}Timing System Performanceint count(int n){ int i; int sum = 0; for (i=0; i<n; i++) { sum += i; } return sum;}main(int argc, char** argv){ ... for (i=0; i<t; i++) { start_counter(); count(n); times[i] = get_counter(); } ...}– 11 –15-213, S’04Timing System Performanceint count(int n){ ...}main(int argc, char** argv){ ...}main(int argc, char** argv){ ...}int count(int n){ ...}Experiment n cycles/n1 10 1649.22 10 17.23 1000 24.34 1000 6.1Experiment n cycles/n1 10 1657.62 10 261a 10 202a 10 16.43a 1000 1.74a 1000 1.6It’s the system, stupid!It’s the system, stupid!– 12 –15-213, S’04Great Reality #3Memory Matters Random Access Memory is anun-physical abstractionMemory is not unboundedIt must be allocated and managedMany applications are memory dominatedMemory performance is not uniformCache and virtual memory effects can greatly affect program performanceAdapting program to characteristics of memory system can lead to major speed improvementsMemory referencing bugs especially perniciousEffects are distant in both time and space– 13 –15-213, S’04Memory Performance ExampleImplementations of Matrix MultiplicationMultiple ways to nest loops/* ijk */for (i=0; i<n; i++) { for (j=0; j<n; j++) { sum = 0.0; for (k=0; k<n; k++) sum += a[i][k] * b[k][j]; c[i][j] = sum; }} /* ikj */for (i=0; i<n; i++) { for (k=0; k<n; k++) { sum = 0.0; for (j=0; j<n; j++) sum += a[i][k] * b[k][j]; c[i][j] = sum }}– 14 –15-213,


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CMU CS 15213 - Introduction to Computer Systems

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