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TAMU BIOL 111 - mRNA Transcription and Translation
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BIOL 111 1st Edition Lecture 14 Outline of Last Lecture I. Before Mendel (<1860s)—ideas about inheritanceII. Gregor Mendel (1822-1884): the Revolutionary monkIII. MeiosisIV. How to geneticists represent alleles?V. Law of segregation Outline of Current Lecture I. Section IV Review: Molecular BiologyII. The Central DogmaIII. The genetic codeIV. Self quizV. Transcription—making mRNAVI. Synthesis of transcriptionVII. Processing RNA in the nucleusVIII. Consequences of RNA splicingCurrent Lecture- Section IV Review: Molecular Biologyo Bridging the gap between DNA and traitso Central dogma of molecular biologyo How are these processes controlled?o How is this information used in the “real world”?- The Central Dogmao DNAmRNAProtein Monomers: Nucleic acidnucleic acidamino acids DNAmRNA goes through transcription  mRNAamino acids goes through translationo Differences in prokaryotes vs. eukaryotes? Present of nucleus in eukaryotes and will make a difference in the transcription and translation process In a prokaryote, transcription and translation occurs at the same time The nuclear envelope separates the process of transcription/RNA processing (occurs inside the envelope) and translation (occurs outside the envelope)- The genetic codeo How many monomers in the molecule of inheritance? There are 4 monomers (ATCG)o How many monomers in the product of translation?o How do you code for 20 amino acids with just 4 nucleic acids?o Triplet code Nt(4) X nt(4) X nt(4) = 64 codon codes Some codons code for the same amino acids  Be able to read codon chart (Fig. 17.5) ORF (open reading frame)=- Start codon + series of codons + stop codon (amino acid) + (amino acid) Codon: 3 nucleotide sequence that specifies a particular amino acid or stop signal Know:- AUG=start codon- UAA, UAG, UGA=stop codons- Self quizo A DNA template strand reads: 3’ TACGTACCGTAATGCCCCATC 5’o What is the sequence of the mRNA that will be transcribed from this sequence of DNA? 5’ AUGCAUGGCUAAUCGGGGUAG 5’o What peptide will be translated from the mRNA Start codon-HIS-GLY-stop codon-SER-GLY-stop codon- Transcription—making mRNAo Molecular components DNA template- Promoter- Terminator RNA polymerase Ribonucleotides (AKA: RNA nucleotides- Synthesis of transcriptiono Initiation  Promoter (TATA box)-a eukaryotic promoter includes a TATA box Transcription factors-several transcription factors must bind to the DNA before RNA polymerase II can do so RNA polymerase II-additional transcription factors bind to the DNA along with RNA polymerase II- RNA polymerase-unwinds DNA, reads DNA, synthesizes RNA (only 5’3’) does not need primero Termination of transcription Prokaryotes: reads terminator sequence and detaches Eukaryotes: read polyadenylation sequence and beyond before detaching- Processing RNA in the nucleuso Modifying the ends Functions: facilitate export to cytoplasm, prevent degradation, help ribosomes attach to mRNA Types of modifications: 5’ cap, polyadenalated tail (also note: 5’ and 5’ UTR)o Modifying the middle (Figs 17.10, 17.11) RNA splicing Exons-expressed portions of transcript Introns-in between expressed portions Spliceosome - Composed of proteins and snRNAs (small nuclear RNA)- Cuts out introns- Consequences of RNA splicingo Alternative splicing possibleOne gene=2 or more


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TAMU BIOL 111 - mRNA Transcription and Translation

Type: Lecture Note
Pages: 3
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