ANALYSIS Go back and look at the parental genotypes and phenotypes Parental Cross to produce F1 generation The geneotypes of the two parents were P1 gl1 gl1 gfp2 gfp2 and P2 gl2 gl2 gfp1 gfp1 1 Construct two Punnett squares for the individual genes in this cross For GFP gfp1 gfp1 Gametes gl2 gl2 Gametes gfp2 gfp1 gfp2 gfp1 gfp2 gfp2 gfp1 gfp2 gfp1 gfp2 gl2 gl1 gl2 gl1 gl2 gl1 gl2 gl1 For Gl gl1 gl1 2 Construct the Punnett square for both Gametes gl1 gfp2 gl1 gfp2 gl1 gfp2 gl1 gfp2 gl2 gfp1 gl2 gfp1 gl2 gfp1 gl2 gfp1 gl2 gl1 gfp1 gfp2 gl2 gl1 gfp1 gfp2 gl2 gl1 gfp1 gfp2 gl2 gl1 gfp1 gfp2 gl2 gl1 gfp1 gfp2 gl2 gl1 gfp1 gfp2 gl2 gl1 gfp1 gfp2 gl2 gl1 gfp1 gfp2 gl2 gl1 gfp1 gfp2 gl2 gl1 gfp1 gfp2 gl2 gl1 gfp1 gfp2 gl2 gl1 gfp1 gfp2 gl2 gl1 gfp1 gfp2 gl2 gl1 gfp1 gfp2 gl2 gl1 gfp1 gfp2 gl2 gl1 gfp1 gfp2 3 Based on your Punnettt square in 3 what PHENOTYPE S will you see in the F1 1 For all of the offspring they would be fluorescent and have trichomes F1 self cross to produce F2 generation 4 What is are the complete GENOTYPES of the two parents in the F1 cross They are both gl2 gl1 gfp1 gfp2 5 Construct two Punnett squares for the individual genes in this cross For GFP For Gl gfp1 gfp2 Gametes gl2 gl1 Gametes gfp1 gfp1 gfp1 gfp1 gfp2 gl2 gl2 gl2 gl2 gl1 gfp2 gfp1 gfp2 gfp2 gfp2 gl1 gl2 gl1 gl1 gl1 6 Construct the Punnett square for both gl2 gfp1 gl2 gfp2 gl1 gfp1 gl1 gfp2 Gametes gl2 gfp1 gl2 gl2 gfp1 gfp1 gl2 gl2 gfp1 gfp2 gl2 gfp2 gl2 gl2 gfp1 gfp2 gl2 gl2 gfp2 gfp2 gl1 gfp1 gl2 gl1 gfp1 gfp1 gl2 gl1 gfp1 gfp2 gl1 gfp2 gl2 gl1 gfp1 gfp2 gl2 gl1 gfp2 gfp2 gl2 gl1 gfp1 gfp1 gl2 gl1 gfp1 gfp2 gl2 gl1 gfp1 gfp2 gl2 gl1 gfp2 gfp2 gl1 gl1 gfp1 gfp1 gl1 gl1 gfp1 gfp2 gl1 gl1 gfp1 gfp2 gl1 gl1 gfp2 gfp2 7 Based on your Punnett square what PHENOTYPES do you expect to see in the F2 I expect to see a phenotypic ratio of 9 offspring with trichomes and fluorescence 3 offspring with trichomes and no fluorescence 3 off spring with no trichomes and fluorescence and 1 offspring with no trichomes and no fluorescence 2 8 The two genes are assorted independently which means that the overall probability of a specific phenotype is the product multiplication of both individual probabilities That is if the probability of one phenotype is green color is and the probability of being tall is then the probability of being green and tall is 1 4 3 4 3 16 Using this multiplication rule calculate the probability of each expected phenotype above Include your work Probability of phenotype with trichomes and fluorescence 3 4 3 4 9 16 Probability of phenotype with trichomes and no fluorescence 3 4 1 4 3 16 Probability of phenotype with no trichomes and fluorescence 1 4 3 4 3 16 Probability of phenotype with no trichomes and no fluorescence 1 4 1 4 1 16 PART II 50 1 What is the total number of seedlings counted 2 Based on total counted and probabilities calculated in 8 above what are your EXPECTED results for the different phenotypes 3 Make a table of your OBSERVED results based on counting the number of different phenotypes Phenotypes GFP GFP 28 9 31 5 trichomes trichomes trichomes trichomes 10 3 9 5 Phenotypes GFP GFP 4 How well do your results match with expected What would make them better 3 My observed results match fairly well aside from a little deviation between some phenotypes This deviation is due to sampling effects the random selection of a subset of individuals and a higher sample size could minimize random chance which can significantly skew the observed phenotypic ratio away from the expected It could also be because certain genotypes have a less than 100 survival rate 4
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