We will consider four types of rearrangements Rearrangements Reading Chapter 14 pp489 508 for two lectures Problem set for two lectures ABCDEFG Deletions CD deleted ABEFG Tandem duplications CD duplicated ABCDCDEFG Inversions CDE inverted ABEDCFG Reciprocal Translocations Deletions Secretory tissues of dipteran insects like Drosophila have polytene chromosomes Deletions deficiencies can be observed in polytene chromosomes DNA undergoes rounds of replication without separating into separate chromosomes While Drosophila has four pairs of chromosomes it has only four polytene chromosomes Therefore all of the copies of both homologs align in polytene chromosomes 1 Calvin Bridges generated maps that defined the physical extents of deletions Deficiencies can be used to map genes swa w and rst map to X chromosome Df female X swa w and rst male Female genotype Score F1 phenotypes male genotype swa Y w Y rst Y Df1 mutant wt wt Df2 mutant mutant wt Df3 wt mutant mutan t swa w rst Df1 Df2 Df3 Deletions are often found in tumor cells Df mapping can be used to order genes Using 3 factor mapping Df mapping and characterizing the physical extent of Dfs Bridges showed the order of genes defined by genetic mapping represented the physical order of genes on the chromosome Duplications Tandem duplications can be generated by asymmetric pairing and crossing over duplication deletion 2 Tandem dublication results in the Bar phenotype Asymmetric pairing and crossing over can generate multiple copies of DNA segments Opsin genes rhodopsin Asymmetric pairing and duplication of genes is thought to generate gene families The red and green genes on the X chromosome are thought to have arisen from an ancestral photoreceptor gene The gene for rhodopsin is located on chromosome 3 This was the first opsin gene to be discovered Because of the similarity in structure and hence sequence of rhodopsin to the color opsins the remaining opsin genes were isolated based on their similarity to rhodopsin Above is a molecular structure of the rhodopsin protein which is embedded in the rods cell s outer membrane Because of their similarity the color opsins adopt a similar structure Color opsin genes Most red green colorblind males lack green genes The blue opsin gene is on chromosome 7 normal Both red and green opsin genes are on the X chromosome There is usually one red gene and one to three green genes The genes are next to each other and arranged head to tail relative to one another single red gene But how did this happen 3 Asymmetric pairing and unequal crossing over of a ancestral gene led its duplication and evolution into red and green genes The extra green genes and the single red found in redgreen colorblind individuals could have been generated by unequal crossing over meiosis Only two of the four chromosomes are shown Chromosome with single red gene Chromosome with two green Homolog pairing of inversion heterozygotes during meiosis or in polytene chromosomes results in inversion loops Inversions can affect gene function Two types of inversions A B C D E F Normal A B E D C F Paracentric A D C B E F Pericentric 4 The consequence of crossing over in the inversion loop is the production of unbalanced gametes Semisterility in plants Zygotic inviability in animals How are lethal mutations and deficiencies maintained Df or lethal female X Could balance mutation with another let1 Df or lethal male 1 4 1 2 Df 1 4 Df Df Survive let1 let2 X let1 let2 Die 1 2 let1 let2 1 4 let1 let1 1 4 let2 let2 If cross the survivers 1 3 will lack Df Eventually will loose the Df if don t have a simpler way to keep track of it But will get recombiants let1 let2 Survive Die Inversions used so don t get recombinant progeny let2 let1 let2 let1 let2 5 Deficiencies and mutations that lead to a lethal phenotype can be maintained using balancer chromosomes let Cy chromosome 2 CyO is a Drosophila chromosome 2 balancer Cy let Good balancer chromosomes usually have 1 A recessive marker usually one or more lethal mutations let so that animals homozygous for this chromosome die 2 A dominant marker to defect animals that carry the chromosome Cy curly wings 3 An inversion or multiple inversions to ensure that recombinant progeny are not produced Cy let All that has been added is a dominant curly wing marker to be able to know Balancer chromosome is present The Df or lethal can be maintained stably over a balancer Df CyO female X Recombinants that generate a normal chromosome lacking the Df are genetically dead Df CyO male 1 4 CyO CyO 1 2 Df CyO 1 4 Df Df let Cy Die Survive curly wings Df Cy let Die Robertsonian Translocation 6 A 14 21 Robertsonian chromosome produces an inherited form of Down syndrome 7
View Full Document
Unlocking...