Making linkage analysissimpleMaking linkage analysissimple(Do Ch. 5 problems!)Bakers’ yeastA single-celled eukaryoteHaploid and diploidFig. 5.14Haploid and diploidFig. 5.14Clonal (mitotic) growthHaploid and diploidFig. 5.14Haploid and diploidFig. 5.14Why yeast?Tetrad analysisFig 5.15Tetrad analysisFig 5.15Tetrad analysisFig 5.15CannotmakehistidineCannotmaketryptophanTetrad analysisFig 5.15Tetrad analysisFig 5.15Tetrad analysisFig 5.15Tetrad analysisFig 5.15Tetrad analysisFig 5.15Tetrad analysisNPD = 4 recombinant progenyFig 5.15Tetrad analysisFig 5.15Tetrad analysisFig 5.15T = 2 recomb, 2 non-recombTetrad analysis exampleFig 5.15Tetrad analysis example“Number of recombinants = NPD•4 + T•2”Fig 5.15Tetrad analysis example“Number of recombinants = NPD•4 + T•2”“RF = NPD•4 + T•2 ”4•Total # tetradsFig 5.15Tetrad analysis example“Number of recombinants = NPD•4 + T•2”“RF = NPD•4 + T•2 ”Total # tetrads4•Total # tetrads= NPD + 1/2T ”Fig 5.15Tetrad analysis example 2Fig. 5.16Tetrad analysis example 2If PD >> NPD, genes are linked.Fig. 5.16Tetrad analysisFig 5.15If linked, second law does not hold;<< 50% recombinantsTetrad analysisWhat if two crossovers?Fig 5.15Accurate genetic distances?“Number of recombinants = NPD•4 + T•2”“RF = NPD•4 + T•2 ”Total # tetrads4•Total # tetrads= NPD + 1/2T ”Where’s PD?The real story: mapping functionsFig. 5.17Do Ch. 5, problem 35…Bread moldBread moldFig. 5.14Bread moldFig. 5.14Each pair is identicalMapping centromeric distanceFig. 5.21Mapping centromeric distanceFig. 5.21Mapping centromeric distanceFig. 5.21Number of meioses with second-division patterns = number ofcrossovers between locus and
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