PHA 5127-Fall 2004Case Study #2 Answer Key PHA 5127-Fall 2004 1 a.) Systemic clearance = hepatic clearance for this drug. 1.14 L/hr/kg * 62 kg = 70.7 L/hr b.) Fh = 1-Eh Clh = Qh*Eh Fh = 1- (Clh/Qh) = 1-(70.7 L/hr/1500 ml/min) 1500 ml/min = 90 L/hr Fh = 1 – (70.7/90) = 1-0.785 = 0.215 2. For low E drug, Clh = fu*Cli For high E drug, Clh = Qh Parameter Direction of change effect on Clh for a low E drug effect on Clh for ahigh E drug fudecrease decrease no change Cliincrease increase no change Qhdecrease no change decrease 3. a) Systemic clearance = hepatic clearance for this drug Cl = ke *Vdke = 0.693/ 15.6 hours = 0.044 hr-1 Vd = 25 L/kg * 70 kg = 1750 L Cl = 0.044 hr-1 * 1750 L = 77.7 L/hr b) High clearance because it is close to liver blood flow. c) Clh = Qh * Eh 77.7 L/hr = 90 L/hr *EhE = 77.7/90 = 0.86 d) Fh = 1- Eh = 1-0.86 =
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