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PHA 5127 Answers Case Study 2 Fall 2007 1. Patient A.M. is given a 60 mg dose of gentamicin. The volume of distribution for this patient is 10 L and the concentration after 8 hours is 1.4 mg/L. Calculate the ke. What is the half-life? Answer: Co=Dose/(Volume of distribution)=60mg/10L=6mg/L C=Co*e-ke*t (lnC-lnCo)=-ke*t → -(lnC-lnCo)/t=ke → ke=-(ln1.4mg/L-ln6mg/L)/8 hours → ke=0.182 hours-1 t1/2=0.693/ke → t1/2=0.693/0.182 hours-1=3.81 hours 2. Assuming a one compartment body model and a 1st order process, please graph the following on semilog paper and predict the concentration after 6 hours. Time (hours) Concentration (mg/L) 1 80 3 42 5 22 Answer=~16 mg/L 3. Using 110 mg/L as the starting concentration and a ke of 0.318 hour-1 calculate the concentration after 6 hours. Answer: C=Co*e-ke*t C=110 mg/L * e(-0.318hour^-1*6hour)=16.3 mg/L 4. True of False a. In a one-compartment body model it is assumed that a drug distributes to all areas of the body instantaneously. True. b. Pharmacodynamics is the study of the time course of a drug’s absorption, distribution, metabolism, and elimination. False. Pharmacodynamics refers to the relationship between concentration at the site of action and the resulting effect.c. The ke of a drug is 0.00333 min-1. After 2 hours 67% of the drug is remaining in the body. True. Answer: e-ke*t=fraction remaining e(-0.00333 min-1*60 min/hour*2


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UF PHA 5127 - Case Study 2

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