EE100Su08 Lecture #13 (July 25th 2008)Slide 2Slide 3Slide 4Slide 5Slide 6Example CircuitSlide 8Slide 9Break Point ValuesExample: Circuit in Slide #2 MagnitudeBode Plot: Label as dBSlide 1EE100 Summer 2008 Bharathwaj MuthuswamyEE100Su08 Lecture #13 (July 25th 2008)•Outline–MultiSim licenses: postponed to Monday, July 28th 2008•Apparently our license number is not working!•Thanks for coming to lecture today!–HW #2: regrade deadline: Monday, 07/28, 5:00 pm PST.–Midterm #1 regrades: I will finish em by office hours today.–QUESTIONS?–Strain Gauge and Project: Lab Lecture•WARNING: BE REALLY CAREFUL AROUND THE STRAIN GAUGE SINCE THE APPARATUS “STICKS OUT” OF THE TABLE!–Frequency Response and Bode plots–Nonlinear circuits•Reading–Chapter 9 from your book (skip 9.10, 9.11 (duh)), Appendix E* (skip second-order resonance bode plots)–Chapter 1 from your reader (skip second-order resonance bode plots)Slide 2EE100 Summer 2008 Bharathwaj MuthuswamySlide 3EE100 Summer 2008 Bharathwaj MuthuswamySlide 4EE100 Summer 2008 Bharathwaj MuthuswamySlide 5EE100 Summer 2008 Bharathwaj MuthuswamySlide 6EE100 Summer 2008 Bharathwaj MuthuswamySlide 7EE100 Summer 2008 Bharathwaj MuthuswamyExample Circuit)1()/1)/1(22CRjACjRjwCAINOUTVVINOUTnctionTransferFuVV+AVTR2R1+VT+VOUTCVIN+cRcINOUTZZAZVVA = 100R1 = 100,000 OhmsR2 = 1000 OhmsC = 10 uFSlide 8EE100 Summer 2008 Bharathwaj MuthuswamyExample Circuit+AVTR2R1+VT+VOUTCVIN+A = 100R1 = 100,000 OhmsR2 = 1000 OhmsC = 10 uFSlide 9EE100 Summer 2008 Bharathwaj MuthuswamyExample Circuit+AVTR2R1+VT+VOUTCVIN+A = 100R1 = 100,000 OhmsR2 = 1000 OhmsC = 10 uFSlide 10EE100 Summer 2008 Bharathwaj MuthuswamyBreak Point Values •When dealing with resonant circuits it is convenient to refer to the frequency difference between points at which the power from the circuit is half that at the peak of resonance. •Such frequencies are known as “half-power frequencies”, and the power output there referred to the peak power (at the resonant frequency) is•10log10(Phalf-power/Presonance) = 10log10(1/2) = -3 dB.Slide 11EE100 Summer 2008 Bharathwaj MuthuswamyExample: Circuit in Slide #2 Magnitude)1(2CRjAINOUTVV11010010000.11010010001Radian FrequencyA = 100R2 = 1000 OhmsC = 10 uFwp = 1/(R2C) = 100AMagnitudeActual value = 2100|1|100 jSlide 12EE100 Summer 2008 Bharathwaj MuthuswamyBode Plot: Label as dB0204060-201010010001Radian Frequency)1(2CRjAINOUTVVA = 100R2 = 1000 OhmsC = 100 uFwp = 1/(R2C) = 100AMagnitude in dBNote: Magnitude in dB = 20
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