Chem 1211 1st Edition Lecture 18 Outline of Last Lecture I Atomic Spectra II Quantization Steps III Wave Nature of Electrons Outline of Current Lecture I Quantum numbers II Energy of orbitals Current Lecture I II Quantum numbers a n row or shell b l shape s p d f g h c m l l d spin number 1 2 or 1 2 e ConcepTest Which orbital has the quantum numbers ml 1 l 1 n 4 i 4s ii 4p iii 4d iv 3d 1 ANSWER ii 4p 2 REASONING n is just the row a l 0 s 1 p 2 d 3 f 4 g f ConcepTest What are acceptable quantum numbers for a 4d orbital i Answer n 4 l 2 mI 0 ii ml just has to be between l and l or in this case 2 and 2 Energy of Orbitals Aufbau Principle a Rule 1 fill starting with lowest order of n l b Rule 2 if n l is the same start with lower n c ConcepTest Which two orbitals have the same value for n l i 2s 2p These notes represent a detailed interpretation of the professor s lecture GradeBuddy is best used as a supplement to your own notes not as a substitute ii 2s 3s iii 2p 3p iv 2p 3s 1 ANSWER iv for 2p add 2 1 and for 3s add 3 0 d ConcepTest Place the orbitals 3d 4s 4p and 5s in order of increasing energy i ANSWER 4s 3d 4p 5s ii REASONING find the energy level by adding n l 3d 5 4s 4 4p 5 5s 5 4s is the lowest and because the others have equal energies you follow Rule 2 and put them in order of increasing n e ConcepTest Which element has 3d orbitals occupied by electrons i F ii Cl iii Br iv K v Ca 1 ANSWER iii Br 2 REASONING energy increases in order 1s2 2s2 3p6 3s2 3p6 4s2 3d 4p 3 According to periodic table Br is in p block and it is in the 4th row so it is 4p To get here you must have filled 3d f What is the electron configuration for chlorine i 1s22s22p5 ii He 2s22p5 iii 3s23p5 iv Ne 3s23p5 v Ne 3s13p6 1 ANSWER Ne 3s23p5 2 Reasoning noble gases are completely filled He 1s2 Ne 1s22s22p6 Chlorine is all of Neon plus 3s2 and 3p5 g Which transition metal has the electron configuration Kr 4d55s1 i ANSWER Mo
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