Chem 1211 1st Edition Lecture 4 Outline of Last Lecture I. SubstancesII. MixtureIII. SI UnitsIV. NumbersV. Arithmetic FunctionsVI. Unit ConversionsOutline of Current Lecture I. Unit Factor MethodII. PercentagesIII. PropertiesIV. Heat UnitsV. Transfer Equation ConstantsCurrent LectureI. Unit Factor Methoda. Ex: Express 627 ml in liters and quartsi. 627ml x (1 L/ 1000ml) = .627 Lii. 627 ml x (1 L/1000 ml) x (1.06 quarts/ 1 L) gives you the answer in quartsb. Convert 60 mph to km/si. (60 miles/ 1 hr) x (1km/ .621 miles) x (1hr/ 360 sec) gives you the answerII. Percentagesa. Percentages are the part per hundredi. Ex. 85%ii. 85/100 is a ratiob. Ex. Seawater contains 1 mg of gold per 1000 kg of water. What percentage does that represent?i. 1 mg x (1 gram/1000 mg) x (1kg/1000g) = 1 x 10-6 kgThese notes represent a detailed interpretation of the professor’s lecture. GradeBuddy is best used as a supplement to your own notes, not as a substitute.ii. (1x10-6 kg gold/1000 kg water) is a ratio; multiply it by 100 to get a percentiii. The answer is 10-7c. Ex. Sterling silver contains 92.5 % silver and 7.5 % copper. A typical fork wighs 4 grams and the price of silver is $0.72 per gram. What is the value per dozen of the forks?i. Silver in forks = .925 x 45 gii. 12 x .925 x 45g x .72 = $359.63 (answer)III. Properties: Applied Matha. Density = mass/ volumeb. Heat capacity = q (heat) = m (mass) x c x t (change in temperature)IV. Heat Units a. Joule (4.184 J = 1 cal)b. Calorie (1000 calories= 1 kilocalorie = 1 Calorie)V. Transfer equation constantsa. Temperature is a measure of heatb. Heat is a form of energyc. Water has a high heat
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