DOC PREVIEW
UGA CHEM 1211 - Balancing Equations
Type Lecture Note
Pages 2

This preview shows page 1 out of 2 pages.

Save
View full document
View full document
Premium Document
Do you want full access? Go Premium and unlock all 2 pages.
Access to all documents
Download any document
Ad free experience
Premium Document
Do you want full access? Go Premium and unlock all 2 pages.
Access to all documents
Download any document
Ad free experience

Unformatted text preview:

Chem 1211 1st Edition Lecture 7 Outline of Last Lecture I. Percent CompositionII. Formulas from Elemental Composition Outline of Current Lecture I. Balancing EquationsCurrent LectureI. Balancing Equationsa. ConcepTest: For this reaction that describes a steelmaking process (a)Fe2O3 + (b)C (c)Fe + (d)CO2, which coefficients represent the balanced equation?i. Answer: a=2, b=3, c=4, d=3b. ConcepTest: For the reaction P4 + 6 Cl2  2 PCl3, in which the product begins to burn, what went wrong?i. Answer: Nothing went wrong… the reaction occurred, and it gave off enough heat to ignite c. ConcepTest: For this reaction that describes a steelmaking process, 2 Fe2O3 + 3 C  4 Fe +3 CO2, what percentage of the mass of the products escapes to the atmosphere? i. Answer: 37%ii. Reasoning: The total mass of the products is (4 x mass of Fe) + (3 x mass of C) + (6 x mass of O) = 355.4g. 1. The part of the product that escapes to the atmosphere is 3 CO2; take the total mass of 3 CO2 and divide it by the total mass of the products.2. This gives you .37; multiply by 100 to get the percentage, and the answer is 37%d. Law of Conservation of Massi. Matter is not created or destroyedii. Balanced chemical equationsiii. Formulated by Antoine Lavoisier in 1789e. ConcepTest: This reaction describes the formation of ammonia: 2H2 + N2  2 NH3. At equilibrium, which of the following are TRUE?These notes represent a detailed interpretation of the professor’s lecture. GradeBuddy is best used as a supplement to your own notes, not as a substitute.i. Three H2 and one N2 are required to form each NH3ii. Some H2 and N2 still exist as those moleculesiii. Some NH3 is reverting back to H2 and N21. Answer: ii and iii (this is a equilibrium


View Full Document

UGA CHEM 1211 - Balancing Equations

Type: Lecture Note
Pages: 2
Download Balancing Equations
Our administrator received your request to download this document. We will send you the file to your email shortly.
Loading Unlocking...
Login

Join to view Balancing Equations and access 3M+ class-specific study document.

or
We will never post anything without your permission.
Don't have an account?
Sign Up

Join to view Balancing Equations 2 2 and access 3M+ class-specific study document.

or

By creating an account you agree to our Privacy Policy and Terms Of Use

Already a member?