Domenica DiStasio 31138525Stress estimate project Method and Results sections: In-class lab worksheetConcepts: independent samples t-test, Pearson’s correlationA) Method Data Processing section*We will do this together as a class *ALL of the steps need to go in a “Data Processing” section of Method section.1. Look at the survey questions: Which ones need to be reverse coded?The ones that need to be reverse coded are items 4,5, 6, 7, 9, 10 and 13. 2. What steps did we take to reverse code them?The steps we took to reverse code them were going into transform andthen recode into the same variable and changing the values. We made 0=4, 1=3, 3=1, and 4=0. 3. Now, we need to calculate the Mean Score. How did we do this?We calculated the mean score by going into transform, compute variable, and then putting in “MEAN(Item 1-14). B) Descriptive Analyses1. Each row is one participant’s data. How many participants in total? 2452. In what order would you like to explore the social media accounts? Why?The 2 social media accounts I am going to explore are Instagram and Facebook. I am picking these two because I know the most about them and Ithink they are two of the higher stressors. 3. Go to Analyze > Descriptive statistics > Frequencies > pull your first variable over to the right side and select OKHow many participants in each group?217 (Instagram)4. Go to Analyze > Descriptive statistics > Frequencies > pull your second variable over to the right side and select OKHow many participants in each group?235 (Snapchat)6. Go to Analyze > Descriptive statistics > Frequencies > pull your third variable over to the right side and select OKHow many participants in each group?218 (Facebook)7. Go to Analyze > Descriptive statistics > Frequencies > pull your fourth variable over to the right side and select OKHow many participants of each group?138 (Twitter)C) Inferential Analyses: Categorical Variables1. T-tests: What two categorical variables will you be testing?The two variable we are testing is number of accounts and number of hours spent on it. T-TEST #1: a. Go to Analyze > Compare Means > Independent samples t-testb. Select variables1. Put the average stress variable in the “test variable” box2. Put your variable in the “grouping variable”A. DEFINE GROUPSB. Enter 0 for group 1, 1 for group 2C. Select CONTINUE à OKDomenica DiStasio 31138525T-TEST #1: C. First, look at the means and standard deviations:Instagram What was the average time for the GROUP 1 condition? M = 1.9554 SD = .70448 What was the average time for the GROUP 2 condition? M = 1.8878 SD = .60339d. Next, look at the box labeled “Independent samples t test”**Look at the top row (ignore the bottom row)t = .539 df = 242 p = .591Is the p –value above or below .05? aboveWhat is the % likelihood that our results are due to chance? 59.1%Does this suggest the results are significant or not? These results are not significant because the p value is not below .05. [For your Discussion section: Why might this be?]The impact of having an Instagram did not affect stress. e. Create a statistical statement of the finding: t(242)=.539, p=.591T-TEST #2f. Follow these same steps for your second comparison. Facebook What was the average time for the GROUP 1 condition? M = 1.7457 SD = .67514 What was the average time for the GROUP 2 condition? M = 1.9152 SD = .606g. Next, look at the box labeled “Independent samples t test”**Look at the top row (ignore the bottom row)t = -1.309 df = 241 p = .192Is the p –value above or below .05? above What is the % likelihood that our results are due to chance? 19.2%Does this suggest the results are significant or not? These results are not significant because the p value is not below .05.[For your Discussion section: Why might this be?]The impact of having a Facebook account did not affect stress. h. Create a statistical statement of the finding: t(241)=1.309, p=.192Domenica DiStasio 311385252. Correlations: What two continuous variables are you analyzing (e.g. sleep, exercise, social media use)?The two continuous variables we are analyzing are average stress and hours of sleep. The second variables are avg stress and exercise. CORRELATION #11. ANALYZE à CORRELATE à BIVARIATE2. Put “AvgStress” and “Hours of Sleep” under VARIABLES3. Click OKLook at your output. What is r (“Pearson correlation”)? r is -.280What is p? .000 (<.001)Is the p –value above or below .05? BelowWhat is the % likelihood that our results are due to chance? There is a 0% likelihood that these results are due to chance. Does this suggest the correlation is significant or not? This suggests that the correlation is significant. What is the direction of the correlation [is r positive or negative]? The direction of the correlation is negative. Write your statistical statement: r=-.280, p= <.001[For your Discussion section: Why might this be?]The amount of sleep you get is correlated with your stress levels (negatively). CORRELATION #2Repeat the steps above for your second variable. What is r? .021What is p? .749Is the p –value above or below .05? aboveWhat is the % likelihood that our results are due to chance? 74.9%Does this suggest the correlation is significant or not? This suggests the correlation is not significant. What is the direction? The direction of the correlation is positive. Write your statistical statement: r=.021, p= .749[For your Discussion section: Why might this be?]Exercise does not affect stress levels. D) Figures and Tables Section1. Generate a graph of the relationship between sleep and stressA. GRAPHS à LEGACY DIALOG à SCATTER à SIMPLE SCATTERB. Under Y – axis put ”Hours of sleep”C. Under X-axis put “AvgStress”Does this graph look how you expected it to from the Pearson’s correlation for sleep and stress?Yes this graph does look the way we expected it too because it does have a negative correlation (which is what we expected). Format the figure in APA style and include it in your report.Domenica DiStasio