7 03 Exam 1 Review SOLUTIONS 1 You are studying a completely penetrant human disorder that is rare in the general population but relatively common in certain regions Woman 1 whose mother s brother was afflicted with this disorder is trying to determine the probability that she and her husband would have an affected child Woman 1 s husband s sister ultimately died of the disease Woman 1 s father is from a low risk population but everyone else in the pedigree is from a region where the disorder is common Besides the two individuals mentioned no one else in this pedigree including the parents of the affected individuals is was affected with the disease All cases of this disorder are suspected to be caused by mutations in the same gene a Draw the pedigree of this family indicating the genotypes of individuals where possible Aa Aa AA Aa Aa aa aa 1 b Is this disorder recessiveWoman or dominant Is it X linked or autosomal Autosomal recessive c If the couple s first child is affected what is the probability that the couple s second child will be affected 1 4 The only way to get an affected child is if both of the parents are carriers The probability of getting an affected child from two carriers Aa x Aa is 1 4 d What is the probability that the couple s first child will be affected 1 18 2 3 probability that Woman 1 s mother is a carrier 1 2 probability that Woman 1 is a carrier if her mom is a carrier 2 3 probability that the husband is a carrier 1 4 the probability they will have an affected child if they re carriers 2 3 x 1 2 x 2 3 x 1 4 1 18 e If the couple s first child is not affected what is the probability that Woman 1 is a carrier of the disease 5 17 x mom is a carrier y one unaffected child p x 2 3 x 1 2 1 3 p not x 2 3 x 1 2 1 3 2 3 For p y x we need to take into account the probability the father is a carrier or homozygous for the unaffected allele p y x 1 2 x 2 3 x 1 2 1 2 x 2 3 x 1 2 1 2 x 2 3 x 1 2 5 6 p y not x 1 p x y 5 6 x 1 3 5 6 x 1 3 1 x 2 3 2 You have isolated three mutants his1 his2 and his3 that are unable to grow without the amino acid histidine You mate each of these with a wild type strain of the opposite mating type and analyze the resulting diploid for its ability to grow without histidine You get the following results Mating his1 x wildtype his2 x wildtype his3 x wildtype Diploid s phenotype WT WT His a What does this tell you about each of the mutations Dominance test his1 recessive his2 recessive his3 dominant b You mate his1 with a his2 strain of the opposite mating type The resulting diploid is unable to grow on histidine What does that tell you about these two mutations Complementation test You get the mutant phenotype out so they don t complement Therefore they should be in the same gene c You decide to mate your his1 and his3 mutants and then sporolate the resulting diploids You analyze the resulting tetrads for their ability to grow without histidine 1 X No Growth 2 3 4 5 Growth 7 8 9 6 X X X X X X X X X X X X X O X X X X X X X X X X O X X X X X X X X X X X P D P D P D T T P D P D NP D P D P D 1 0 X O X X 1 1 X X X X 1 2 O X X X 1 3 X X X O 14 O X O X 1 5 X X X X 1 6 X X O X 1 7 X X X X 1 8 X X X X TT P D TT TT NP D P D TT P D P D d How many PD TT and NPD are there PD 11 TT 6 NPD 1 e Are these two genes linked If so then by how far Yes PD NPD 6 6 x 1 2 x 18 x 100 33cm 4 Wild type Drosophila have red eyes and white eyes is an X linked recessive phenotype caused by a single mutation A new single mutation that gives the recessive phenotype of apricot colored eyes is isolated A female from a truebreeding apricot eyed strain is crossed to a male from a true breeding whiteeyed strain All of the resulting F1 flies have apricot eyes a Are the white eye and apricot eye mutations in the same gene or in different genes Explain your answer same gene they fail complementation since they don t give wt red eyes A collection of apricot eyed F1 females from the cross described above are mated to males from a true breeding white eyed strain and 1000 male progeny are examined Among these progeny only 6 flies have normal red eyes b What is the measured distance between the white eye and apricot eye loci in cM Recombination in the mother is the only way to get red eyed flies The recombination would have to take place between the apricot and white mutations This crossover will give one wt chromosome and one double mutant chromosome Since we have 6 red eyed wt flies we can assume that we have 6 double mutants adding to 12 recombinant offspring in total Distance cM of Recombinants x 100 12 1000 x 100 1 2 cM Total offspring A new mutation is isolated that causes the recessive eye color peach A female from a true breeding peach eyed strain is crossed to a male from a true breeding white eyed strain All of the resulting F1 females have normal red eyes and all of the resulting F1 males have peach eyes c Is the peach eye mutation on an autosome or on the X chromosome Explain your answer X chromosome the females and males exhibit different phenotypes d Are the white eye and peach eye mutations in the same gene or in different genes Explain your answer Different genes they complement each other in the females A mutation that causes the recessive phenotype of crossveinless wings lies on the Xchromosome A female from a true breeding strain with apricot eyes and crossveinless wings is crossed to a male from a single mutant true breeding strain with white eyes and normal wings As expected all of the F1 females from this cross have apricot eyes and normal wings A large collection of these F1 females are crossed to wild type males and 10 000 male progeny are examined The observed phenotypes are as follows Normal wings Crossveinless wings …
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