PHSX 211 10th Edition Lecture 18 Outline of Last Lecture Practice ProblemsI. If you are at a carnival and want to knock down a piece of wood which ball (of equal mass and velocity) would you choose between a rubber bouncy ball and a sticky clay ball?II. A 40 kg girl is on an 8.4 kg sled going at 20 m/s. The girl jumps off the sled and right afterjumping has a speed of 25 m/s in the original direction of motion. What is the velocity ofthe sled?III. If you have Car 1 of 1000 kg moving East at 14 m/s and Car 2 of 1500 kg moving North at11 m/s and they collide and get their bumpers locked, what will their final velocity be?Outline of Current Lecture Practice ProblemsI. A 50 kg archer standing on frictionless ice shoots a 100 g arrow at a speed of 100 m/s. What is the recoil speed of the archer?II. A particle initially at rest explodes into three directions. One momentum vector is expressed by p1= 3i and the second by p2 = -2i – 2j. What is the third momentum vector?III. Try to Create your own 2-dimensional collision problem that is solvable to help you understand what information is needed in able to solve these types of problems.Current LecturePractice ProblemsThese notes represent a detailed interpretation of the professor’s lecture. GradeBuddy is best used as a supplement to your own notes, not as a substitute.I. A 50 kg archer standing on frictionless ice shoots a 100 g arrow at a speed of 100 m/s. What is the recoil speed of the archer?a. The momentum of the archer has to equal to momentum of the arrow so:b. P(archer) = p(arrow)c. m(archer)v(archer) = m(arrow)v(arrow)d. (50)(-v) = (.1)(100)e. V = -0.2 m/sII. A particle initially at rest explodes into three directions. One momentum vector is expressed by p1= 3i and the second by p2 = -2i – 2j. What is the third momentum vector?a. P(final) =P(initial)b. P1 + p2 + p3 = P(initial)c. i: 3 -2 + p3 = 0 ; p3 = -1d. j: 0 + -2 + p3 = 0 ; p3 = 2e. p3 = -1i +
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