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KU PHSX 211 - Forces: Practice Problems
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PHSX 211 1st Edition Lecture 9 Outline of Last Lecture Practice ProblemsI. If you know all the forces acting on a moving object, can you tell in which direction the object is moving?II. What is the net force in the y and x direction acting on the object below centered at the origin? III. Force components Fx = 1.12 N and Fy = 0.12 N act on an object of 3 kg; find acceleration.IV. George is climbing a vine that can supply a maximum tension of 1500 N. If George’s massis 90 kg, what is the largest acceleration he could have?V. If George has acceleration downward of -2.2 m/s2, what is the force due to tension?Outline of Current Lecture Practice ProblemsI. If you are in an elevator standing on a scale in the following situations (1-5), which of thefollowing are true?a. Scale’s measured weight is less than your true weightb. Scale’s measured weight is greater than your true weightc. Scale’s measured weight is equal to your true weighti. If the elevator is stationary?ii. If the elevator is free falling?iii. If the elevator is accelerating upward?iv. If the elevator is accelerating downward?v. If the elevator is rising at a constant speed?II. If there is a block of a mass of 1 kg and a force of 5N is acting on it from the left, and the velocity of the block is zero:a. What must the force of static friction be?b. What is the coefficient of static friction?Current LecturePractice ProblemsI. If you are in an elevator standing on a scale in the following situations (1-5), which of thefollowing are true?a. Scale’s measured weight is less than your true weightThese notes represent a detailed interpretation of the professor’s lecture. GradeBuddy is best used as a supplement to your own notes, not as a substitute.b. Scale’s measured weight is greater than your true weightc. Scale’s measured weight is equal to your true weighti. If the elevator is stationary?1. C2. Because the elevator is an inertial frame of reference and there is no acceleration, the normal force is equal to the force due to gravity ii. If the elevator is free falling?1. A2. Because as you are free falling, the force vector of gravity is greater than the normal source vector, which is the force the scaleis measuringiii. If the elevator is accelerating upward?1. B2. Because the normal force is greater than the force due to gravity, and that is why there is an acceleration upwardiv. If the elevator is accelerating downward?1. A2. Because there is an acceleration downward, the force due to gravity is greater than the normal force, so the scale reads a smaller valuev. If the elevator is rising at a constant speed?1. C2. Because there is no acceleration so the net forces are zeroII. If there is a block of a mass of 1 kg and a force of 5N is acting on it from the left, and the velocity of the block is zero:Fs = ?F = 5N1 kga. What must the force of static friction be?i. Net Force = maii. a = 0, so Net Force = 0iii. Fs = 5Nb. What is the coefficient of static friction?i. Fs = ᶣnii. Fs = ᶣ (m*g)iii. 5N =ᶣ (1kg*9.8 m/s2)iv. ᶣ =


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