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KU PHSX 211 - Constant Acceleration and Projectile Motion
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BIOM 121 1nd Edition Lecture 3 Outline of Last Lecture I. Vectorsa. Have both size and directionII. Scalarsa. Have size but no directionIII. Operationsa. Add, Subtract, Multiplyb. Using Trig to Find Unknown Valuesc. Helpful Equationsd. Equations for splitting up x and y componentse. Component vectosf. Unit vectorsOutline of Current Lecture I. Constant Accelerationa. Equations for distance and velocityb. Horizontal accelerationc. Vertical accelerationII. Examplea. Sketch acceleration and velocity vectorsIII. Projectile Motiona. Horizontalb. VerticalIV. ExampleCurrent LectureI. Constant accelerationa. Equations for distance and velocityx=x0+v0t+(12)a t2These notes represent a detailed interpretation of the professor’s lecture. GradeBuddy is best used as a supplement to your own notes, not as a substitute.v =v0t+atb. Horizontal acceleration = 0c. Vertical acceleration = -9.8066 m/s2 II. Example:a. Sketch acceleration and velocity vectors for:i. Car traveling to the right at rest at stoplight and hits the gasii. Car traveling to the right breaks for a stoplightIII. Projectile Motiona. Horizontal: relatively constant motionb. Vertical: decreases to zero than increases back to starting magnitudeIV. Example:a. If you throw a baseball horizontally at a speed of 25 m/s and it lands 50 m away, how high did you release the ball?avavi. Write down what we know1. a = 9.8 m/s2, vi = 25 m/s, x = 50 m, t = 2 seconds (25 m/s for 50 m)ii. Write an equation1.∆ x=v0t +(12)a t2iii. Solve Equation for the vertical1.H=(0)t +(12)g t22.H=(12)(9.8)(2)23.H=19.6


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