PHSX211 1nd Edition Lecture 8 Outline of Last Lecture I. Which of the following Examples are in an inertial reference frame?a. A car at constant velocity on level ground traveling straightb. A car at constant velocity up an incline of 10 degreesc. A car stepping on the gas as a stoplight turns greend. A car at constant speed traveling around in curvee. A balloon rising straight up at a constant velocityf. A skydiver just after he jumped out of a planeg. A space shuttle orbiting the worldII. If you have a ¾ of a circular tube (that would complete a full circle if all the tube was there) and you shoot a ball through the tube where would the ball travel as it exits the tube (assuming the tube doesn’t move)? III. What forces are acting on a rock that is tossed from your hand at the moment after it has reached its highest point and has started to travel back down?Outline of Current Lecture Practice ProblemsI. If you know all the forces acting on a moving object, can you tell in which direction the object is moving?II. What is the net force in the y and x direction acting on the object below centered at the origin? III. Force components Fx = 1.12 N and Fy = 0.12 N act on an object of 3 kg; find acceleration.IV. George is climbing a vine that can supply a maximum tension of 1500 N. If George’s massis 90 kg, what is the largest acceleration he could have?V. If George has acceleration downward of -2.2 m/s2, what is the force due to tension?Current LecturePractice ProblemsThese notes represent a detailed interpretation of the professor’s lecture. GradeBuddy is best used as a supplement to your own notes, not as a substitute.I. If you know all the forces acting on a moving object, can you tell in which direction the object is moving?a. No, it depends on the magnitudes of each force and on the reference frame.II. What is the net force in the y and x direction acting on the object below centered at the origin? Fx = max = F3cos(θ2) – F1cos(θ1)Fy = may = F1sin( θ1) + F3sin(θ2) – F2III. Force components Fx = 1.12 N and Fy = 0.12 N act on an object of 3 kg; find acceleration.a. Resultant vector: 1.122 + 0.122 = F2b. F = 1.13 Nc. Θ = tan-1(Fy/Fx)d. Θ = 6.12 degreese. Answer: 1.13 N at 6.12 degrees above positive x-axis.IV. George is climbing a vine that can supply a maximum tension of 1500 N. If George’s massis 90 kg, what is the largest acceleration he could have?a. F = mab. Net Force: Tension – Weighti. Net Force = 1500 N – (90 kg)(9.8 m/s2) = 618 N (upward)F1F3Θ1Θ2F2c. 618 N = (90 kg)ai. a = 6.87 m/s2d. Answer: 6.87 m/s2V. If George has acceleration downward of -2.2 m/s2, what is the force due to tension?a. Tension = Weight + mab. Tension = (90 kg)(9.8 m/s2) + mac. Tension = 882 N + (90 kg)(-2.2 m/s2)d. Answer: Tension = 684