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WMU PHYS 1070 - Exam

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X1.14a 107PHYS-107(14) (Kaldon-14959) Name ____________________________________________________WMU - Summer I 2003 Book Title ________________________________________________Exam 1 - 100,000 points Rev. 05/18/02 Su.6-r1State Any Assumptions You Need To Make – Show All Work – Circle Any Final AnswersUse Your Time Wisely – Work on What You Can – Be Sure to Write Down EquationsShort Answers Should Be Short! – Feel Free to Ask Any QuestionsEXAM 1 [FORM - A]PHYS-107 (KALDON-14)SUMMER I 2003WMUMonster Trucks · BigfootPhysics 107 / Exam 1 [Form-A] Summer I 2003 Page 2Now Pay Attention – You Can Do This (30,000 points) Multiple-Guess-Fill-In-The-Bubbles1.)(a) Rocko drives his car for 2.00 miles at 30.0 mph. How many minutes does it take to travelthis distance? The handy chart at left may be useful.A = 1.00 min B = 2.00 min C = 3.00 min D = 4.00 minE = 5.00 min F = None of these(b) Robin drives her car for 2.00 miles accelerating from rest to 120. mph. How many minutesdoes it take to travel this distance?A = 1.00 min B = 2.00 min C = 3.00 min D = 4.00 minE = 5.00 min F = None of these(c) Roland drove 2.00 miles accelerating from rest to 120. mph and then 2.00 miles deceleratingfrom 120. mph back down to zero. How many minutes does it take?A = 1.00 min B = 2.00 min C = 3.00 min D = 4.00 minE = 5.00 min F = None of these(d) Ralph drives 0.500 mile at 30.0 mph, 0.500 mile at 45.0 mph, 0.500 mile at 60.0 mph and0.500 mile at 120. mph How many minutes does it take?A = 1.00 min B = 2.00 min C = 3.00 min D = 4.00 minE = 5.00 min F = None of theseFor each of the following, select the answer A-D that BEST represents the motion.(e) John is climbing a tree, making a steady pace. This is an example of __________ Motion.A = No B = Uniform C = Constant AccelerationD = None of these(f) John is falling out of the tree. This is an example of __________ Motion.A = No B = Uniform C = Constant AccelerationD = None of these(g) John is lying on the ground under the tree, resting. This is an example of __________ Motion.A = No B = Uniform C = Constant AccelerationD = None of theseFor each of the following, select the answer A-F that BEST represents the quantity.(h) An object in free fall from rest is moving with a speed of _________ after 1.00 seconds.A = +9.81 m B = -9.81 m C = +9.81 m/sD = -9.81 m/s E = +9.81 m/s²F = -9.81 m/s²(i) The acceleration in the y-direction of an object in free-fall is ________.A = +9.81 m B = -9.81 m C = +9.81 m/sD = -9.81 m/s E = +9.81 m/s²F = -9.81 m/s²(j) An object moving with an acceleration in the x-direction of 2g will travel ________ after 1.00 seconds.A = +9.81 m B = -9.81 m C = +9.81 m/sD = -9.81 m/s E = +9.81 m/s²F = -9.81 m/s²mph sec25 144.030 120.035 102.940 90.045 80.050 72.055 65.560 60.065 55.470 51.475 48.080 45.085 42.490 40.095 37.9100 36.0105 34.3110 32.7115 31.3120 30.0125 28.8130 27.7135 26.7225 16.0! " # $ % &! " # $ % &! " # $ % &! " # $ % &! " # $ % &! " # $ % &! " # $ % &! " # $ % &! " # $ % &! " # $ % &Physics 107 / Exam 1 [Form-A] Summer I 2003 Page 3“Monster Trucks!” (35,000 points)2.) Dr. Phil was, as usual, cruising the cable channels looking forinspiration for good test problems, when he found a program on theBigfoot Monster Truck races. The course is 340. feet long (104 meters).The huge Ford hemi motors have up to 1500 horsepower and can get thetrucks from 0 to 60 mph (26.8 m/s) in 3.00 seconds. (a) What is thisacceleration?(b) How far does the Bigfoot move in those 3.00 seconds? How much of the 104 meter course is there to go?(c) If the Bigfoot finishes the race at its cruising speed of 60 mph (26.8 m/s), how much time does that take?(d) This Bigfoot truck has jumped 18.0 feet (5.49 meters) in the air. What v0y would allow any object to jump 5.49 m up in the air?(e) If the jump has a v0 x = 26.8 m/s, find the velocity vector rv0in Standard Form. If you did not get an answerto (d), use v0 y = 13.4 m/s.Physics 107 / Exam 1 [Form-A] Summer I 2003 Page 4Soviet Space Secrets (35,000 points)3.) (a) During a “normal” launch into space (as if any launch into space is “normal”!!), the payload has to beaccelerated from rest to an orbital speed of 7880 m/s (about 17,600 mph) in 8.00 minutes. Find the averageacceleration of this launch.(b) Find the distance that the rocket traveled, if it spent 8.00 minutes at this average acceleration. If you did notget an answer to (a), use a = 20.0 m/s².(c) In 1983, the Soviet Soyuz T-10A was all set to be launched, when a fire broke out on the launch pad tenminutes before launch. An emergency escape rocket finally blasted the Soyuz and the cosmonauts on board twothousand feet into the air (610. meters) just six seconds before the main booster blew up. Ignoring air resistanceand parachutes, as usual, find the time it takes to fall to the ground from rest at a height of 610. meters.(d) At what speed would an object in free-fall from rest at 610. meters hit the ground? This can be found even ifyou don’t have the answer to (c).(e) On another mission, the booster rocket taking the Soyuz 18A capsule into space failed on the way up. Againthe capsule was safely jettisoned in time, but the emergency maneuver had a peak deceleration at a brutal 20.6gee’s. At this rate, how long (time) would it take for them to slow down from 8000 mph (3580 m/s) to wherethe parachutes can open at 340 mph (152


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