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WMU PHYS 1070 - Exam

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X1.18a 1070PHYS-1070(18) (Kaldon-20592) Name _______ __S O L U T I O N__ ____________WMU - Summer I 2006 Book Title ________________________________________________Exam 1 - 100,000 points Rev. 05/17/06 We.5State Any Assumptions You Need To Make – Show All Work – Circle Any Final AnswersUse Your Time Wisely – Work on What You Can – Be Sure to Write Down EquationsShort Answers Should Be Short! – Feel Free to Ask Any QuestionsEXAM 1 [FORM - A]PHYS-1070 (KALDON-18)SUMMER I 2006WMUThe New Vespa!Physics 1070 / Exam 1 [Form-A] Summer I 2006 Page 2Now Pay Attention – You Can Do This (30,000 points) Multiple-Guess-Fill-In-The-Bubbles1.)(a) Sam drives his car for 2.00 miles at 40.0 mph. How many minutes does it take to travel thisdistance? The handy chart at left may be useful. 90.0 sec/mile × 2 miles = 180 sec = 3 min.A = 1.00 min B = 2.00 min C = 3.00 min D = 4.00 minE = 5.00 min F = None of these(b) Sarah drives her car for 2.00 miles accelerating from rest to 80.0 mph. How many minutesdoes it take to travel this distance? Average speed = 40 mph, so 2 miles in 3 min.A = 1.00 min B = 2.00 min C = 3.00 min D = 4.00 minE = 5.00 min F = None of these(c) Stuart drove 2.00 miles accelerating from rest to 80.0 mph and then 2.00 miles deceleratingfrom 80.0 mph back down to zero. How many minutes does it take? Twice (b).A = 1.00 min B = 2.00 min C = 3.00 min D = 4.00 minE = 5.00 min F = None of these(d) Susan drives 0.500 mile at 40.0 mph, 0.500 mile at 45.0 mph, 0.500 mile at 90.0 mph and0.500 mile at 120. mph How many minutes does it take? ½ × (90.0 sec + 80.0 sec + 40.0 sec+ 30.0 sec) = ½ × (240 sec) = 120 sec = 2.00 min.A = 1.00 min B = 2.00 min C = 3.00 min D = 4.00 minE = 5.00 min F = None of theseFor each of the following, select the answer A-D that BEST represents the motion.(e) John is climbing a tree, making a steady pace. This is an example of __________ Motion.A = No B = Uniform C = Constant AccelerationD = None of these(f) John is falling out of the tree. This is an example of __________ Motion.A = No B = Uniform C = Constant AccelerationD = None of these(g) John is lying on the ground under the tree, resting. This is an example of __________ Motion.A = No B = Uniform C = Constant AccelerationD = None of theseFor each of the following, select the answer A-F that BEST represents the quantity.(h) An object in free fall from rest is moving with a speed of _________ after 1.00 seconds.A = +9.81 m B = -9.81 m C = +9.81 m/sD = -9.81 m/s E = +9.81 m/s²F = -9.81 m/s²(i) The acceleration in the y-direction of an object in free-fall is ________.A = +9.81 m B = -9.81 m C = +9.81 m/sD = -9.81 m/s E = +9.81 m/s²F = -9.81 m/s²(j) An object moving with an acceleration in the x-direction of 2g will travel ________ after 1.00 seconds.A = +9.81 m B = -9.81 m C = +9.81 m/sD = -9.81 m/s E = +9.81 m/s²F = -9.81 m/s²d = ½ a t² = ½ (2g) t² = g t² = 9.81m/s² × (1.00sec)²mph sec25 144.030 120.035 102.940 90.045 80.050 72.055 65.560 60.065 55.470 51.475 48.080 45.085 42.490 40.095 37.9100 36.0105 34.3110 32.7115 31.3120 30.0125 28.8130 27.7135 26.7225 16.0! " f $ % &! " f $ % &! " # $ % i! e # $ % &! e # $ % &! " f $ % &d " # $ % &! " f g % &! " # $ % id " # $ % &Physics 1070 / Exam 1 [Form-A] Summer I 2006 Page 3“Magnifico!” (35,000 points)2.) (a) The Vespa Granturismo 200 is a new scooter from the famous Italian maker.The company’s specifications give the maximum speed as 74.0 mph (119 km/h = 33.1 m/s).If the Vespa accelerates from rest to 33.1 m/s in 16.6 seconds, find the acceleration, a.v v at at or avtavtmsms=+ = === =0233116 61994DD./.sec./(b) How far does the Vespa travel in this time? This can be found with or without the answer to (a).xx vt atxat msm=+ +===0012212212221994 16 6274 7./ .sec.chbgORvv axxvaxxvamsmsm2020222222233121994274 7=+ -=== =()././.bgch(c) What is the average speed of the Vespa while it is accelerating?vdtmms===274 716 616 55..sec./ OR vvvv msmsave=+===022331216 55././(d) Unfortunately, having too much fun, Vincent runs his brand newVespa straight off a cliff with v0x = 33.1 m/s, where it falls 18.0 feet (5.49meters) to the ravine below. Find the y-component of the velocity, vy, justbefore it impacts the ground.vv gyygy gyvgy msmms msyyy20200002220 22298154910 38 10 38=- -=- - ====± =-()()./ ../ ./chbgPhysics 1070 / Exam 1 [Form-A] Summer I 2006 Page 4(e) Find the final velocity, rv, just before it impacts the ground. Give the answer in Standard Form. If you didnot get an answer to (d), use a vertical speed of 13.4 m/s.vvv ms msmsxy=+= +-=2222331 10 3834 69./ . /./bgb g q =FHGIKJ=-FHGIKJ=- °= °--tan tan././..1110 3833117 4 342 6vvmsmsyxrvms= 34 69 342 6./@.Soviet Space Secrets (35,000 points)3.) (a) During a “normal” launch into space (as if any launch into space is “normal”!!), the payload has to beaccelerated from rest to an orbital speed of 7880 m/s (about 17,600 mph) in 8.00 minutes. Find the averageacceleration of this launch.v v at at or avtavtmsms=+ = === =02788048016 42DD/.sec./(b) Find the distance that the rocket traveled, if it spent 8.00 minutes at this average acceleration. If you did notget an answer to (a), use a = 20.0 m/s².xx vt atxat msm=+ +===00122122122216 42 4801892 000./ .sec,,chbgORvv axxvaxxvamsmsm202022222227880216421 891 000=+ -====()/./,,bgchPhysics 1070 / Exam 1 [Form-A] Summer I 2006 Page 5(c) In 1983, the Soviet Soyuz T-10A was all set to be launched, when a fire broke out on the launch pad tenminutes before launch. An emergency escape rocket finally blasted the Soyuz and the cosmonauts on board twothousand feet into the air (610. meters) just six seconds before the main booster blew up. Ignoring air resistanceand parachutes, as usual, find the time it takes to fall to the ground from rest at a height of 610. meters.yy vt gtygtygttygtygmmsy=+ -=-==== =0012201220122200202226109811115../.secbg(d) At what speed would an object in free-fall from rest at 610. meters hit the ground? This can be found even ifyou don’t have the answer to (c).v v gt gtmsmsy=- =-=-=-02981 1115109 4./ .sec./chbgORvv gyygy gyvgy ms mms msyyy20200002220 222981610109 4 109 4=- -=- - ====± =-()()./ ../ ./chbga speed of 109.4 m/s is acceptable(e) On another mission, the booster rocket taking the Soyuz 18A capsule into space failed on the way up. Againthe capsule was safely jettisoned in time, but the emergency maneuver had a peak deceleration at a brutal 20.6gee’s.


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