XF.16b 107PHYS-107(15) (Kaldon-) Name ____________S O L U T I O N ___________WMU - Fall 2003Final Exam - 200,000 points CHECK-OUT: T1 T2 Q23 _________Rev. 12/07/03 Su.6State Any Assumptions You Need To Make – Show All Work – Circle Any Final AnswersUse Your Time Wisely – Work on What You Can – Be Sure to Write Down EquationsShort Answers Should Be Short! – Feel Free to Ask Any QuestionsFINAL EXAM [FORM - B] NOONPHYS-107 (KALDON-16)FALL 2003WMUThe New L.A.F.D. Fireboat 2 – Launched 2003Physics 107 / Final Exam [Form-B] Fall 2003 Page 2“Almost Over” (50,000 points) Multiple-Guess-Pick-The-Best-Answer-Fill-In-The-Bubbles1.) In parts (a)-(d), select which Newton’s Law or Conservation Law best applies.(a) Both cars get dented in a collision because of the forces in…A = Newton’s 1stB = Newton’s 2ndC = Newton’s 3rdD = Momentum E = Energy F = None of these(b) Ballistic motion is also an example of…A = Newton’s 1stB = Newton’s 2ndC = Newton’s 3rdD = Momentum E = Energy F = None of these(c) If there are no non-conservative forces doing work, then…A = Newton’s 1stB = Newton’s 2ndC = Newton’s 3rdD = Momentum E = Energy F = None of these(d) A centripetal force shows up at the result of sum of forces equation when using…A = Newton’s 1stB = Newton’s 2ndC = Newton’s 3rdD = Momentum E = Energy F = None of theseIn parts (e)-(h), select which speed best represents the situation described.(e) “Oh man, I have to run if I am going to make it to my Physics Final in time!”A = 1.5 m/s B = 6.0 m/s C = 25. m/s D = 250 m/s E = 340 m/sF = 11,000 m/s(f) “Did you hear that?”A = 1.5 m/s B = 6.0 m/s C = 25. m/s D = 250 m/s E = 340 m/sF = 11,000 m/s(g) “All I want to do after this test is get on a flight and fly south to where it’s warm.”A = 1.5 m/s B = 6.0 m/s C = 25. m/s D = 250 m/s E = 340 m/sF = 11,000 m/s(h) “Just strolling along watching the rain fall.”A = 1.5 m/s B = 6.0 m/s C = 25. m/s D = 250 m/s E = 340 m/sF = 11,000 m/sUse vector rA with an x-component Ax = 27.0 m and a y-component Ay = -25.0 m in the follow problems:(i) The magnitude of this velocity vector is A = __________ .A = 2.00 m B = 10.2 m C = 36.8 mD = 52.0 m E = 104 m F = 1354 m(j) The Standard Angle for rA is ________.A = 42.8° B = 47.2° C = 132.8°D = 137.2° E = 312.8° F = 317.2°! " f $ % &! " # $ h &! " # $ h &! e # $ % &! e # $ % &! " # $ h &! " # g % &d " # $ % &! " f $ % &! " # $ % iPhysics 107 / Final Exam [Form-B] Fall 2003 Page 3“Fireboat 2 – See the Fire in the Port of Los Angeles.” “Roger, copy.” (50,000 points)2.) On March 21, 2003, the world's most powerful dedicatedfireboat was accepted for delivery by its Owner, the LosAngeles Fire Department, and began its delivery voyage fromFreeland, Washington near Seattle to its home port of LosAngeles. The big monitor or water jet at the right of the photoshoots a stream of water out at a speed of 103 mph (46.1 m/s).In real life, including air resistance, the stream of water travelsa horizontal range of 600 feet. Use the range equation or thekinematic equations and find the maximum distance d that anyobject with v0 = 46.1 m/s can travel.600 feet = 183.0 mRvgmsmsm==´°=02222461 2 45981216 6sin./ sin( )./.qbgb gvv gtv v v vvvgtvgttvgmsmsdvtORxx vt atxvt v tms myy y y yyyyyxxx=- =- = °-= --=-== ===++== °==000000002001220045222461 45981664645461 45 6 646 216 6;;sin./sin./.seccos. / sin . sec .bgbgbgbgbgb g(b) The big monitor delivers water in an 8 inch (20.0 cm = 0.200 m) diameter stream with a force of 7500 lbs.(33,400 N). Using the definition of pressure, show that this is close to the 10 atmospheres in the designspecifications. 1 atmosphere = 101,300 Pa.ArD mr mPFANmPaD== ==== =pp2220 200 010033 40001001063000;., .,.,,bg(c) Use Bernoulli’s Equation and find the pressure P1 needed to blow water out at v2 = 46.1 m/s. Use a pressureof P2 = 0, so P1 becomes a gauge pressure and can be compared to (b). For fresh water, rwater = 1000 kg/m³.Pgh vPgh vPv kgm msPa1112122212221122212321000 4611063000++ =+ +===rr rrr /./,,chbgPhysics 107 / Final Exam [Form-B] Fall 2003 Page 4(d) The press release from the designers give the overall length as 105 feet (32.0 m), width as 29.0 feet (8.84 m)and depth below waterline as 13.3 feet (4.06 m). If the volume of the submerged part of the boat is 680. m³,find the mass of water that is displaced by this boat in fresh water.rr====mVmVmkgmm kg;(/)(.),1000 680 680 00033(e) The main engines on LAFD #2 are V-12 MTU/Detroit Diesel Model 12V4000 diesel engines, each rated at1,800 hp (1,343 kW). If the actual efficiency of this engine is 46.0% (0.460), then find the power wasted inWatts. Remember that Actual Efficiency works for both Work & Energy (Joules) and Power (Watts).eeActualHActualHCWQUseful PowerTotal PowerTotal PowerUseful Power WWQWQTotal Power Useful Power Waste PowerWaste Power Total Power Useful PowerWW W======+=+=-=-=1 343 00004602 920 0002 920 000 1 343 000 1 577 000,,.,,,, ,, ,,Physics 107 / Final Exam [Form-B] Fall 2003 Page 5Physics Train Wreck (50,000 points)3.) A freight train is rolling through Kalamazoo MI at 100. mph(44.7 m/s). The locomotive and the five cars weigh 2,000,000 N.A pickup truck (mass = 1700 kg) has stalled on the track 100.meters in front of the train, on the railroad crossing. Interestinginformation: Train brakes use all the wheels of the train on allcars. Steel wheels on steel rail: µs = 0.74 and µk = 0.57.(a) At a distance of 100. meters, the engineer applies the brakes, but they lock up the wheels and also blows thetrain’s horn to warn the driver of the pickup truck. How long does it take for the sound to reach the pickuptruck? The speed of sound on this day at 0°C is 334 m/s.dvttdvmms=== =10033402994./.sec(b) If the horn has a resonant tube open at both ends of length L and the sound has a frequency of 400. Hz, findthe length L if this wave is a fundamental.vfvfmsHzmLmm=== === =lll33440008350208350204175/...(c) The train cannot come to a stop in 100. meters. Find the speed of the train just before it hits the truck. Thebraking force is equal to 0.57 × weight of the entire train.ORFF N NwmgmwgNmskgFmaaFmNkgms gvv axxvms msmmssns== ==== ====-=- =-=+ -=+-=mm0 57 2 000 000 1140 0002000000981203 9001140 000203 9005591244 7 2 5591 10029 6622202022.,, ,,;,,./,,,,./()./ (. /)(.)./bgbgbgbgWFd KE mv mvvvFdmvmsNmkgms== = -=+=+=D .../(, , )( . ),./12212022022244 72 1140 000 100203 90029 66bgPhysics 107 /