X2.15a 107PHYS-107(15) (Kaldon-) Name __________S O L U T I O N_________WMU - Fall 2003Exam 2A - 100,000 points Book Title ________________________________________________Rev. 10/21/03 M.A2State Any Assumptions You Need To Make – Show All Work – Circle Any Final AnswersUse Your Time Wisely – Work on What You Can – Be Sure to Write Down EquationsShort Answers Should Be Short! – Feel Free to Ask Any QuestionsEXAM 2 [FORM - A] 8AMPHYS-107 (KALDON-15)FALL 2003WMUAnd now an important announcement:“Conservation Laws aren’t just for Physicists,They’re for everybody.”What World Series?Physics 107 / Exam 2 [Form-A] Fall 2003 Page 2“Fact or Friction” (50,000 points) Multiple-Guess-Pick-The-Best-Answer-Fill-In-The-Bubbles1.) (a) The Work Energy Theorem says that the Work done on an object changes its ________ Energy.A = Static B = Kinetic C = Potential D = Radial InwardE =Tangent F = Radial Outward(b) The _________ coefficient of friction is always the smaller.A = Static B = Kinetic C = Potential D = Radial InwardE =Tangent F = Radial Outward(c) Rodney the Reindeer goes around and around on his string because there is a ___________ Force.A = Static B = Kinetic C = Potential D = Radial InwardE =Tangent F = Radial Outward This is U.C.M.(d) There is no centrifugal force. If Rodney’s string breaks, his initial motion is _________ to the circle.A = Static B = Kinetic C = Potential D = Radial InwardE =Tangent F = Radial Outward(e) An object tossed straight up, will have only ________ Energy at its turning point.A = Static B = Kinetic C = Potential D = Radial InwardE =Tangent F = Radial Outward At rest at turning point.(f) A woman throws a ball horizontally. The work she does on the ball results in the ball gaining _____Energy.A = Static B = Kinetic C = Potential D = Radial InwardE =Tangent F = Radial Outward Same as in (1a).In parts (g)-(i), select which of Newton’s 3 laws or the 2 Conservation laws that best describes the situation.(g) A car speeding up to merge into the expressway traffic.A = Newton’s 1stB = Newton’s 2ndC = Newton’s 3rdD = Momentum E =Energy F = None of these(h) The force of the Earth on the Moon and the force of the Sun on the Moon.A = Newton’s 1stB = Newton’s 2ndC = Newton’s 3rdD = Momentum E =Energy F = None of these(i) The difference between a totally elastic collision and a totally inelastic collision.A = Newton’s 1stB = Newton’s 2ndC = Newton’s 3rdD = Momentum E =Energy F = None of these(j) A golf ball sitting on a tee, just before it is struck.A = Newton’s 1stB = Newton’s 2ndC = Newton’s 3rdD = Momentum E =Energy F = None of these! e # $ % &! e # $ % &! " # g % &! " # $ h &! " f $ % &! e # $ % &! e # $ % &! " # $ % i! " # $ h &d " # $ % &Physics 107 / Exam 2 [Form-A] Fall 2003 Page 3“Drivin’ Along in My Automobile…” (50,000 points)2.) A car (mass = 2110 kg) is driving along at a constant speed of 67 mph (29.9 m/s). (a) Find the weight of thecar.wmg kg ms N== =2110 9 81 20 7002bgch./ ,(b) The engine has to supply a force of 3450 N just to overcome air resistance. If there wasn’t air resistance,find the acceleration a that a force of 3450 N would have on this car.FmaaFmNkgms=== =3450211016352./(c) The coefficients of friction are 1.00 and 0.820 respectively. What is the maximum braking force that the carcan supply while under complete control?The Maximum Braking Force would be Maximum Static Friction.Fwmg NFF NNNfs s N== ====20 700100 20 70020 700,.,,,,maxmbgb gPhysics 107 / Exam 2 [Form-A] Fall 2003 Page 4(d) A dog runs across the road and the driver stomps on the brake pedal, skidding to a stop in a distance d.Find d.Skidding tells us this would be Kinetic Friction.Fwmg NFF NNFFmaaFmNkgmsNfk k Nxfkxxfk== =====- ==-=-=-å20 7000 820 20 70016 97016 970211080432,.,,,./,,,mbgb gFFmaaFmNkgmsvv axxvaxax vxvamsmsmxfkxxfkxx xxxxxxxå=- ==-=-=-=+ -=+ -=-=-=--=,,,./()()././.16 9702110804320202229 92804355582202002020222bgchOR WKEFd mv mvFd mvdmvFkg m sNm==-=-=-=--=D1221202120202222110 29 92169705558bgb gbg./,.(e) While traveling at a speed of 67 mph (29.9 m/s), the driver falls asleep at the wheel and drifts over to theright, running into a parked SUV (mass = 2890 kg). Find the speed of the wreck, V.pp pmvmv mv m m VVmvmmkg m skg kgmsbefore after==+=+=++=+=;()()()(./)()./11 2 2 1 2111202110 29 92110 289012