X1.d 107Physics 107 (Kaldon-22243) Name ____________________________________________________WMU - Spring 2002 Book Title ________________________________________________Exam 1 - 100,000 points – SAMPLE EXAM Rev. 5/11/00 Th.2State Any Assumptions You Need To Make – Show All Work – Circle Any Final AnswersUse Your Time Wisely – Work on What You Can – Be Sure to Write Down EquationsShort Answers Should Be Short! – Feel Free to Ask Any Questions“Truth or Dare” (25,000 points) Multiple-Guess-Fill-In-The-Bubbles1.)(a) It is 4.00 miles from Bill’s house to Wackie Weenie World where Bill works. On MondayBill drives at a constant 60.0 mph. How many seconds does it take to travel this distance?The handy chart at left may be useful.A = 60.0 sec B = 120. sec C = 240. sec D = 360. secE = 480. sec F = None of these(b) On Tuesday Bill drives the 4.00 miles by constantly accelerating from rest to 120. mph. Howmany seconds does it take to travel this distance?A = 60.0 sec B = 120. sec C = 240. sec D = 360. secE = 480. sec F = None of these(c) On Wednesday Bill drove 2.00 miles accelerating from rest to 120. mph and then 2.00 milesdecelerating from 120. mph back down to zero. How many seconds does it take?A = 60.0 sec B = 120. sec C = 240. sec D = 360. secE = 480. sec F = None of these(d) On Thursday Bill drives 2.00 miles at 120. mph, stops for 2.00 minutes, then drives the last2.00 miles also at 120. mph. How many seconds does it take?A = 60.0 sec B = 120. sec C = 240. sec D = 360. secE = 480. sec F = None of these(e) Terry is having a bad day at his physics test. When he steps outside, he throws his calculator straight up inthe air at v0 = +15.0 m/s. What is the acceleration of the calculator as it goes up?A = +9.8 m/s² B = -9.8 m/s² C = +1.0 m/s² D = -1.0 m/s² E = 0 m/s²F = None of these(f) What is the acceleration of the calculator at the top of its travel?A = +9.8 m/s² B = -9.8 m/s² C = +1.0 m/s² D = -1.0 m/s² E = 0 m/s²F = None of thesemph sec25 144.030 120.035 102.940 90.045 80.050 72.055 65.560 60.065 55.470 51.475 48.080 45.085 42.490 40.095 37.9100 36.0105 34.3110 32.7115 31.3120 30.0125 28.8130 27.7135 26.7225 16.0! " # $ % &! " # $ % &! " # $ % &! " # $ % &! " # $ % &! " # $ % &Physics 107 / Sample Exam 1 Spring 2002 Page 2 “You have the right to remain silent. You have the right to an attorney.” (25,000 points)2.) In class you were shown the classic pursuit problem where a speeding car undergoing Uniform Motionpasses by a stopped police car which then begins Constant Acceleration. (a) To “catch” the speeder, the cop andthe speeder have to be in the same place at the same _____________. (Fill in the blanks for (a) and (b).)(b) One problem with this classic pursuit is that the cop ends up traveling ____________ as fast as the speeder,because the cop was accelerating.(c) Here is a different kind of pursuit problem: A crook and a cop spot each other on the street at the sametime, but the cop is at x = 0.00 m and the crook is at x = 20.0 m. At time t = 0, the crook starts running awayfrom the cop at 6.55 m/s and the cop starts chasing him at 7.55 m/s. VERY briefly explain why it is reasonablethat the cop will catch the crook in 20.0 seconds.(d) Write an equation for x for the crook and solve it for t = 20.0 sec.(e) Write an equation for x for the cop and solve it for t = 20.0 sec. Do you get the same x as in (d)?Physics 107 / Sample Exam 1 Spring 2002 Page 3Neither Rain Nor Sleet Nor Snow Nor Gloom of Night… (25,000 points)3.) A letter starts on its way into the United States Postal Service bypassing through a slot and falling into a mailbox, starting from rest. If theheight that it fell was 0.504 meters, (a) how long (time) did the letter take tofall?(b) How fast was the letter going just before it hit the bottom of the mailbox? You do not need the answer to(a) to solve this.(c) A sorting machine needs to get the letter from rest to 11.0 m/s in a distance of 45.0 cm. What is theacceleration of the letter in this machine?(d) The letter is sent on a truck for 500. miles. Which would get there faster: (I) Traveling half the distance at55.0 mph and half the distance at 70.0 mph or (II) Traveling half the time at 55.0 mph and half the time at 70.0mph? BRIEFLY explain your answer. You may not need to calculate anything to answer this.(e) The letter was mailed at 8:00:00 am on Tuesday and delivered at 10:00:00 am on Thursday ( 50.0 hours )and traveled some 518.7 miles ( 834.6 km ). What was its average speed? Give answer in m/s, of course.Physics 107 / Sample Exam 1 Spring 2002 Page 4 “He’s at the 50… the 40… the 30… he… could… go… all… the… way…” (25,000 points)4.) It’s fourth down and a football player kicks a football to the other team. The football travels 45.0 meters inthe horizontal and 22.2 meters at its highest point in thevertical. (a) How long (time) was the football in the air?(b) What was the initial v0 y of the football right after it was kicked? Note: this can be solved without (a).(c) What is vy at the top of the arc, at y = 22.0 m ?(d) What is the acceleration of the ball in the x-direction, ax ?(e) Find the initial v0 x of the football right after it was kicked. If you didn’t get an answer to (a), then use t =5.50