ECE201 Exam 1 February 9 2010 Division 0101 Prof Capano 9 30am Division 0201 Prof Tan 10 30 am Division 0301 Prof Jung 7 30 am Division 0401 Prof Capano 11 30am INSTRUCTIONS DO NOT OPEN THIS EXAM UNTIL TOLD TO DO SO There are fourteen 14 multiple choice problems worth 7 points each Students who properly identify themselves with name and id number on scantron sheet will receive two extra points To maximize our assessment of your knowledge and understanding do NOT dwell on a single problem If you get stuck move on to the next problem and return later time permitting This is a closed book closed notes exam Calculators are allowed but not necessary All students are expected to abide by the usual ethical standards of the university i e your answers must reflect only your own knowledge and reasoning ability Students caught cheating will receive a grade of F for the course Course Outcomes As described in the course syllabus we must certify that every student who receives a passing grade in this course has satisfied each of the course outcomes On this exam you have the opportunity to satisfy outcomes i ii and iii On the chart below we list the criteria we use for determining whether you have satisfied these course outcomes Course Outcome i ii iii Exam Questions 1 2 4 5 7 9 11 12 6 8 10 13 3 14 Total Points Possible 56 28 14 Minimum Points required to satisfy course outcome 28 14 7 If you fail to satisfy any of the course outcomes don t panic There will be more opportunities for you to do so later on 1 A quantity of positive charge passing through the resistor from B to A is q t 4t in Coulombs B A 10 Find VAB in V 1 2 3 4 5 6 7 8 10 10 20 20 30 30 40 40 2 Determine the unknown current i in A 1 1 7 7 2 2 4 4 3 3 5 5 6 6 6A 4 A 5 A i 1 3 There is a circuit that has only resistors in it It has two input ports one for a voltage input VIN and another one for a current input IIN The output VOUT is measured at two different sets of input conditions and the results are shown below in the table Using the two measurement results find VOUT when VIN 15V and IIN 3A 1 2 V 3 6 V 5 2 V 7 6 V VIN IIN VOUT 20 V 10 V 15 V 2A 4A 3 A 2V 6V 2 4 V 4 8 V 6 4 V 2 4 Find the voltage VBC in V 1 12 2 26 8 A 72 V 3 39 4 48 B 5 C Ix 5 0 6 6 7 24 D 3Ix 10 16 5 In the circuit below it is known that the voltage source supplies a current of 4A to the resistors ALL resistors have the same resistance and the power dissipated by the first resistor is 192 W Find the power delivered by the voltage source in Watts 1 1152 2 288 3 312 4 440 5 572 6 625 7 750 192 W 4 VS 3 6 Find the current ix in the circuit below in A 1 0 33 2 0 33 4 4 3 3 2 5 0 9 6 3 33 7 0 75 100 9 300 ix A 2A B C B 20 ix 100 50 V 20 7 For the circuit shown below find Vout in V 1 Vout 50 Vin 3 Vout 150 Vin 5 Vout 250 Vin 7 Vout 350 Vin 2 Vout 100 Vin 4 Vout 200 Vin 6 Vout 300 Vin 4 8 For the circuit shown below find VAB 1 2 5 V 3 7 5 V 5 4 0 V 7 8 0 V 2 5 0 V 4 2 0 V 6 6 0 V 9 For the circuit shown below find Va 1 20 V 3 60 V 5 100 V 7 140 V 2 40 V 4 80 V 6 120 V 5 10 For the circuit shown below find IX 1 0 5 A 3 1 5 A 5 2 5 A 7 3 5 A 2 1 0 A 4 2 0 A 6 3 0 A 11 Find the value of R3 in the circuit below so that I2 6 A 1 1 2 2 3 3 4 4 5 5 6 6 7 7 8 8 6 12 Find the equivalent resistance Req as seen by the voltage source VS 1 1 2 2 3 3 4 4 5 5 6 6 7 7 8 8 13 The loop equations for the circuit shown below are as follows 25 20 I1 VS 0 1 I I 2 S For R2 20 find the value of R1 1 1 2 2 3 3 4 4 5 5 6 6 7 7 8 8 7 14 We are trying to calculate i1 using superposition First we calculate i1 1 with only the voltage source active as shown in Figure 1 Second we calculate i1 2 with only the current source active as shown in Figure 2 Find i1 1 i1 2 and i1 Figure 1 Figure 2 1 i1 1 1A i1 2 0 6A and i1 1 6A 2 i1 1 2A i1 2 1 2A and i1 3 2A 3 i1 1 1A i1 2 0 6A and i1 0 4A 4 i1 1 2A i1 2 1 2A and i1 0 8A 5 i1 1 1A i1 2 0 6A and i1 0 4A 6 i1 1 2A i1 2 1 2A and i1 0 8A 7 i1 1 1A i1 2 1 2A and i1 2 2A 8
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