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Purdue ECE 20100 - lect6

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EE201 Lecture 6 P 1 Dependent Sources Dependent sources from Lect 3 i t ix i t gm vx VCCS v t vx VCVS CCCS v t rm ix CCVS EE201 Lecture 6 P 2 transconductance gm mho VCCS voltage gain VCVS current gain CCCS transfer resistance rm ohm CCVS Example Find Req when gm equals a 0 5 mmho b 1 0 m mho c 2 m mho IS Answers a 2 k V1 VS b open 1k gmV1 c 1 k Solution From KCL IS gmVS I1k VS 1k IS 1 1k gm VS Req VS IS 1 1k gm 1 EE201 Lecture 6 Example Iin 40 mV P 3 79 8 Vin Iout 3 Vin Vout 47 16 8 Find Req of ind source Iin Iout Vout voltage gain Solution a Req 3 47 50 b Iin 0 04 V 50 0 0008 A 0 8 mA c Iout Gout Geq x 79 8 Vin Vin 47 50 0 04 V 0 0376 V Iout 2A d Vout 2A x 8 16 V e Voltage gain V V 425 5 EE201 Lecture 6 Example I1 Iout I2 3 I1 10 V P 4 5 I2 2 3 2 Find a the output voltage and output current b the voltage gain c the power delivered by each source Solution a I1 10 V 2 5 A I2 3 x 5A 3 5 A Iout 5 I2 25 A Vout Iout x 2 50 V Vout EE201 Lecture 6 P 5 Solution cont b Voltage gain Vout Vin 50 V 10 V 5 c Power delivered by sources Independent voltage source P I12 x R1 5A 2 x 2 50 W Dependent voltage source P I22 x R2 5A 2 x 3 75 W Dependent current source P Iout2 x Rout 25A 2 x 2 1250 W EE201 Lecture 6 Example B 2A A 2 I1 P 6 6A V2 8A 1 0 2I1 V3 E I2 V 1 I3 C 3 I4 0 3I1 4 D Find a the voltage drop V1 b the voltage drop V2 EE201 Lecture 6 Solution Solve for currents first I1 6 A by inspection KCL B to find I2 2A 0 2I1 2A 1 2A I2 I2 3 2A KCL E to find I3 6A 0 2I1 0 3I1 I3 0 I3 3A KCL C to find I4 I 2 I 3 I4 I4 6 2 A P 7 EE201 Lecture 6 P 8 Solution cont Use KVL around closed path B C E B to find V1 VBC VCE VEB 0 2I2 3I3 V1 0 6 4 9 V1 V1 2 6 V Use KVL around closed path E C D E to find V3 VEC VCD VDE 0 9 4I4 V3 0 9 24 8 V3 V3 33 8 V Use KVL around closed path A E D A to find V2 VAE VED VDA 0 V2 V3 8 0 V2 33 8 8 V2 41 8 V


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Purdue ECE 20100 - lect6

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