ECE 201 Fall 2009 Final Exam December 16 2009 Division 0101 Tan 11 30am Division 0201 Clark 7 30 am Division 0301 Elliott 1 30 pm Instructions 1 DO NOT START UNTIL TOLD TO DO SO 2 Write your Name division professor and student ID PUID on your scantron sheet 3 This is a CLOSED BOOKS and CLOSED NOTES exam 4 There is only one correct answer to each question 5 Calculators are allowed but not necessary Please clear any formulas text or other information from your calculator memory prior to the exam 6 If extra paper is needed use back of test pages 7 Formulas are given on the final page of this exam 8 Cheating will not be tolerated Cheating in this exam will result in an F in the course 9 If you cannot solve a question be sure to look at the other ones and come back to it if time permits 10 As described in the course syllabus we must certify that every student who receives a passing grade in this course has satisfied each of the course outcomes On this exam you have the opportunity to satisfy all outcomes See the course syllabus for a complete description of each outcome On the chart below we list the criteria we use for determining whether you have satisfied these course outcomes You only need to satisfy the outcomes once during the course so any outcomes that you satisfied previously will remain satisfied independent of your performance on this exam Course Outcome i ii iii iv v vi vii viii ix Exam Questions 1 3 5 16 4 9 18 27 6 7 11 18 19 22 23 26 27 8 10 Minimum correct answers required to satisfy the course outcome 2 1 2 1 4 2 2 1 1 1 1 Determine the voltage Vz 1 15V 2 10V 3 7 5V 4 5V 5 0 6 5V 7 7 5V 8 10V 9 15V 2 For the circuit shown below the current I is 1 0A 2 2A 3 5A 4 6A 5 6A 6 10A 7 10A 2 3 The voltage Vx in the circuit shown below is 1 33V 2 21V 3 9V 4 3V 5 3V 6 9V 7 21V 8 33V 4 The circuit shown below has two independent sources V1 and I2 The output voltage Vout has been measured for two combinations of input sources V1 I2 Vout 2V 5A 12 V 4V 2 5 A 1 V What would the value of Vout be for V1 1 V and I2 1 A 1 1 V 2 2 V 3 3 V 5 5 V 6 6 V 7 0 V 3 4 4 V 5 The capacitor is uncharged at t 0 i e Vc 0 0 Determine Vc at t 2 sec 1 10 V 2 8 65 V 3 5 V 4 1 35 V 5 0 6 1 35 V 7 5 V 8 8 65 V 9 10 V 6 The switch in the RL circuit shown below has been open for a long time and closes at t 0 s Find the inductor current iL t for t 0 1 2 2e 10t A 2 2 2e 10t A 3 5 4 2e 10t A 6 4 2e 10t A 7 none of the above 4 4 4e 10t A 4 4 4e 10t A 7 Determine the rate of change in the inductor current at t 0 iL 0 diL t in the dt t 0 circuit below 1 0 A s 2 2 A s 3 3 A s 4 5 A s 5 5 A s 6 3 A s 7 2 A s 8 1 A s 8 Given an input voltage of 4V what is the output voltage Vout of this circuit containing an ideal operational amplifier 1 0 2 5 V 3 10 V 4 20 V 5 40 V 6 20 V 7 10 V 8 5 V 5 9 Assume an ideal operational amplifier and that the capacitor is uncharged at t 0 Find the correct expression for the output voltage Vo t in volts for t 0 where t is in seconds 1 t 2 t 3 3 t 1 4 4 4t 2 5 4t 3 6 t 4 7 2t 1 4 10 In the Op Amp circuit below the Th venin equivalent resistance Rth at the inverting input is 1 3 k 2 2 k 3 1 k 4 0 5 k 5 0 k 6 0 5 k 7 1 k 8 2 k 9 3 k 6 11 The current phasor I in the circuit below is 1 j100 A 2 j10 A 3 j1 A 4 0 A 5 j1 A 6 j10 A 7 j100 A 12 At 2 rad s the phasor current through the element shown below is I 2 45 A rms Determine the voltage v t across the element 1 0 2 2sin 2 t V 3 2 2 cos 2 t V 4 2sin 2 t 45 V 5 2 cos 2 t 45 V 6 2 2 sin 2 t 45 V 7 2 2 cos 2 t 45 V 7 13 The phasor current I for the node sketched below has a magnitude of 1 0 A 2 1 A 3 4 2 A 5 5 A 6 7 A 3A 7 12 A 14 The mesh current phasor I1 in the circuit below is 1 1 0 A 2 2 0 A 3 j1 A 4 j2 A 5 1 j A 6 1 2j A 7 2 j A 8 2 2j A 8 15 At 2 rad s the impedance ZTH j 2 j2 shown in the circuit below can be realized with 1 a single 1 resistor 2 a single 2 resistor 3 a single 1 inductor 4 a single 2H inductor 5 a 1 resistor in series with a 1 inductor 6 a 1 resistor in series with a 2 inductor 7 a 2 resistor in series with a 1 inductor 8 a 2 resistor in series with a 2 inductor 9 16 The circuit below contains a floating voltage source The voltage phasors at nodes A and B are VA and VB respectively The correct nodal equation involving the super node containing both nodes A and B is 1 VA 5 0 V 2 VB 10 0 V 3 1 j VA jVB 5 0 V 4 1 j VA 1 j VB 15 0 V 5 2 j VA jVB 5 0 V 6 2 j VA 2 j VB 15 0 V 7 1 2j VA 2jVB 5 0 V 8 1 2j VA 1 2j VB 15 0 V 17 In the circuit shown below let is t 2 5 cos t A with the frequency variable As is varied we measure the amplitude of the voltage across the capacitor as shown in the plot to the right Determine C 1 1 F 2 2 F 3 5 F 4 10 F 5 20 F 6 50 F 7 100 F 8 …
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