Subject Weight: 777.9 NewtonsConversion: 174.9 lbs * 4.448 = 777.9 NDumbbell Weight: 20 poundsConversion: 20 lbs * 4.448 = 88.96 NNumber of Steps: 10 StepsHeight per Step: 0.2 m/stepCompute the mechanical work and power for each trial and report all of the relevant data in thetable below (use area below chart if you want to show work: not required).ConditionTrialTime(s)Displacement (m)Force(N)Work (J)Power(W)Unweighted11.72 s2 m777.9N1,555.8 J904.53 W21.98 s2 m777.9N1,555.8J785.76W31.80 s2 m777.9N1,555.8J864.33 Naverage1.83 s2 m777.9N1,555.8J851.54WDumbbell12.15 s2 m866.91N1,733.83J806.43W22.475s2 m866.91N1,733.83J700.54W32.25 s2 m866.91N1,733.83J770.59Waverage2.29 s2 m866.91N1,733.83J759.19WBriefly answer the following questions. Write your answers neatly in the spaces provided.1. Do the mechanical work and power values vary from trial-to-trial and betweenconditions? Explain why they do or do not.a. The mechanical work values do not vary from trial-to-trial, but they do varybetween conditions. This is because you calculate work values based off of theforce values and the force values do not vary from trial-to-trial because it is basedoff of body weight (body weight does not change). Work values do vary betweenconditions because you are adding 20 pounds to your body weight in the secondcondition which will increase your force. Also, work is based off of distance andmass and neither of these values are being changed during trials. Next, themechanical power values do vary from trial-to-trial and also between the differentconditions. This is due to calculating the power based off of the work and thetime. In regards to trial-to-trial calculations, the power will change because eventhough our work value stays constant, the time it takes for each trial varies.Between the two conditions, the work values and the time values are both beingchanged so therefore our mechanical power values will also vary.2. Do you think the results of either of these TESTs are a good indication of YOURmaximal anaerobic capacity (i.e., your maximal power output)? Explain why or why notand if not, what sort of test would be (you may want to think in terms of exercisephysiology just as much as biomechanics)?a. I believe that these tests are not a good indication of my maximal anaerobiccapacity. The first reason I think this is because I am not used to climbing stairs aspart of the way that I exercise. When I choose to workout, I am either completinglong distance bike rides (5 plus miles) or I am completing strength exercises usingdumbbells - this form of test does not match up with the way that I am used toexercise. I was also not prepared mentally to complete this test on this day so Icould have performed better if I was more prepared with a warm-up. The test thatwould show more accurate results of my maximal anaerobic capacity would bethe wingate test due to the fact that I feel more comfortable on a bike than I dospring up the stairs.3. Calculations (clearly indicate your answer and show your work in the space provided):a. How many total calories did you burn to complete all 6 trials (assume: 0.000239Kcal/J & only 25% efficiency).i. Weighted1. 1,555.8 J * 0.000239 Kcal/J = 0.372 Kcal2. 0.372 Kcal * 3 trials = 1.116 Kcalii. 20 pound dumbell1. 1,733.83 J * 0.000239 kcal = 0.414 Kcal2. 0.414 * 3 trials = 1.242 Kcaliii. Total Calories1. 1.116 Kcal + 1.242 Kcal = ~2.358 Caloriesb. Using the Law of Conservation of Mechanical Energy formula (e.g. kineticenergy = potential energy), calculate what your velocity would be just prior toimpact would be if you fell to the ground from the height of the stairs.i. Total energy (work done) = potential (mgh) + kinetic (mv^2/2)ii. (1/2) 79.33 V^2 = (79.33 x 9.81 x 2m)iii. 39.66 (V^2) =1556.45iv. V2 = 39.24v. V = 6.264
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