Copyright © Cengage Learning. All rights reserved. 16.3 The Fundamental Theorem for Line Integrals2 2 The Fundamental Theorem for Line Integrals Recall that Part 2 of the Fundamental Theorem of Calculus can be written as where F ! is continuous on [a, b]. We also called Equation 1 the Net Change Theorem: The integral of a rate of change is the net change.3 3 The Fundamental Theorem for Line Integrals If we think of the gradient vector ∇f of a function f of two or three variables as a sort of derivative of f, then the following theorem can be regarded as a version of the Fundamental Theorem for line integrals.4 4 Example 1 Find the work done by the gravitational field in moving a particle with mass m from the point (3, 4, 12) to the point (2, 2, 0) along a piecewise-smooth curve C. Solution: We know that F is a conservative vector field and, in fact, F = ∇f, where5 5 Example 1 – Solution Therefore, by Theorem 2, the work done is W = ∫C F ! dr = ∫C ∇f ! dr = f (2, 2, 0) – f (3, 4, 12) contd6 6 Independence of Path7 7 Independence of Path Suppose C1 and C2 are two piecewise-smooth curves (which are called paths) that have the same initial point A and terminal point B. We know that, in general, ∫C1 F ! dr ≠ ∫C2 F ! dr. But one implication of Theorem 2 is that ∫C1∇f ! dr = ∫C2∇f ! dr whenever ∇f is continuous. In other words, the line integral of a conservative vector field depends only on the initial point and terminal point of a curve.8 8 Independence of Path In general, if F is a continuous vector field with domain D, we say that the line integral ∫C F ! dr is independent of path if ∫C1 F ! dr = ∫C2 F ! dr for any two paths C1 and C2 in D that have the same initial and terminal points. With this terminology we can say that line integrals of conservative vector fields are independent of path. A curve is called closed if its terminal point coincides with its initial point, that is, r(b) = r(a). (See Figure 2.) Figure 2 A closed curve9 9 Independence of Path If ∫C F ! dr is independent of path in D and C is any closed path in D, we can choose any two points A and B on C and regard C as being composed of the path C1 from A to B followed by the path C2 from B to A. (See Figure 3.) Figure 310 10 Independence of Path Then ∫C F ! dr = ∫C1 F ! dr + ∫C2 F ! dr = ∫C1 F ! dr – ∫–C2 F ! dr = 0 since C1 and –C2 have the same initial and terminal points. Conversely, if it is true that ∫C F ! dr = 0 whenever C is a closed path in D, then we demonstrate independence of path as follows. Take any two paths C1 and C2 from A to B in D and define C to be the curve consisting of C1 followed by –C2.11 11 Independence of Path Then 0 = ∫C F ! dr = ∫C1 F ! dr + ∫–C2 F ! dr = ∫C1 F ! dr – ∫C2 F ! dr and so ∫C1 F ! dr = ∫C2 F ! dr. Thus we have proved the following theorem. Since we know that the line integral of any conservative vector field F is independent of path, it follows that ∫C F ! dr = 0 for any closed path.12 12 Independence of Path The physical interpretation is that the work done by a conservative force field as it moves an object around a closed path is 0. The following theorem says that the only vector fields that are independent of path are conservative. It is stated and proved for plane curves, but there is a similar version for space curves.13 13 Independence of Path We assume that D is open, which means that for every point P in D there is a disk with center P that lies entirely in D. (So D doesnt contain any of its boundary points.) In addition, we assume that D is connected: this means that any two points in D can be joined by a path that lies in D. The question remains: How is it possible to determine whether or not a vector field F is conservative? Suppose it is known that F = P i + Q j is conservative, where P and Q have continuous first-order partial derivatives. Then there is a function f such that F = ∇f, that is, and14 14 Independence of Path Then there is a function f such that F = ∇f, that is, and Therefore, by Clairauts Theorem, The converse of Theorem 5 is true only for a special type of region.15 15 Independence of Path To explain this, we first need the concept of a simple curve, which is a curve that doesnt intersect itself anywhere between its endpoints. [See Figure 6; r (a) = r (b) for a simple closed curve, but r(t1) ≠ r(t2) when a < t1 < t2 < b.] Figure 6 Types of curves16 16 Independence of Path In Theorem 4 we needed an open connected region. For the next theorem we need a stronger condition. A simply-connected region in the plane is a connected region D such that every simple closed curve in D encloses only points that are in D. Notice from Figure 7 that, intuitively speaking, a simply-connected region contains no hole and cant consist of two separate pieces. Figure 717 17 Independence of Path In terms of simply-connected regions, we can now state a partial converse to Theorem 5 that gives a convenient method for verifying that a vector field on is conservative.18 18 Example 2 Determine whether or not the vector field F (x, y) = (x – y) i + (x – 2) j is conservative. Solution: Let P (x, y) = x – y and Q (x, y) = x – 2. Then Since ∂ P/∂ y ≠ ∂ Q/∂ x, F is not conservative by Theorem 5.19 19 Conservation of Energy20 20 Conservation of Energy Lets apply the ideas of this chapter to a continuous force field F that moves an object along a path C given by r (t), a ≤ t ≤ b, where r (a) = A is the initial point and r (b) = B is the terminal point of C. According to Newtons Second Law of Motion, the force F(r(t)) at a point on C is related to the acceleration a(t) = r & (t) by the equation F(r(t)) = m r & (t) So the work done by the force on the object is21 21 Conservation of Energy Therefore where v = r ! is the velocity. (Fundamental Theorem of Calculus) (By formula [u(t) ! v(t)] = u!(t) ! v(t) + u(t) ! v!(t)) (By formula [u(t) ! v(t)] = u!(t) …
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