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UIUC MATH 241 - 12_05

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PowerPoint PresentationSlide 2Equations of Lines and PlanesSlide 4Slide 5Slide 6Slide 7Slide 8Slide 9Slide 10Slide 11Slide 12Slide 13PlanesSlide 15Slide 16Slide 17Slide 18Slide 19Copyright © Cengage Learning. All rights reserved. 12Vectors and the Geometry of SpaceCopyright © Cengage Learning. All rights reserved. 12.5Equations of Lines and Planes33Equations of Lines and PlanesLearning objectives:Given information about a line, find a vector equation, parametric equations, and symmetric equations for the line, and equations for a line segmentFind a direction vector of a given lineGiven information about a plane, find a vector equation, scalar equation, and linear equation for the planeFind a normal vector given an equation for a plane, and points on a given plane44Equations of Lines and PlanesA line in the xy-plane is determined when a point on the line and the direction of the line (its slope or angle of inclination) are given.The equation of the line can then be written using the point-slope form.Likewise, a line L in three-dimensional space is determined when we know a point P0(x0, y0, z0) on L and the direction of L. In three dimensions the direction of a line is conveniently described by a vector, so we let v be a vector parallel to L.55Equations of Lines and PlanesLet P(x, y, z) be an arbitrary point on L and let r0 and r be the position vectors of P0 and P (that is, they haverepresentations and ).If a is the vector with representation as in Figure 1,then the Triangle Law for vector addition gives r = r0 + a.Figure 166Equations of Lines and PlanesBut, since a and v are parallel vectors, there is a scalar t such that a = t v. Thuswhich is a vector equation of L.Each value of the parameter t gives the position vector rof a point on L. In other words, as t varies, the line is traced out by the tip of the vector r.77Equations of Lines and PlanesIf the vector v that gives the direction of the line L is writtenin component form as v = a, b, c, then we have t v = t a, t b, t c.We can also write r = x, y, z and r0 = x0, y0, z0, so the vector equation becomesx, y, z = x0 + t a, y0 + tb, z0 + t cTwo vectors are equal if and only if corresponding components are equal.88Equations of Lines and PlanesTherefore we have the three scalar equations:where t  These equations are called parametric equations of theline L through the point P0(x0, y0, z0) and parallel to thevector v = a, b, c.Each value of the parameter t gives a point (x, y, z) on L.99Equations of Lines and PlanesThe vector equation and parametric equations of a line arenot unique. If we change the point or the parameter orchoose a different parallel vector, then the equations change.1010Equations of Lines and PlanesAnother way of describing a line L is to eliminate theparameter t from Equations 2.If none of a, b, or c is 0, we can solve each of theseequations for t, equate the results, and obtainThese equations are called symmetric equations of L.1111Equations of Lines and PlanesNotice that the numbers a, b, and c that appear in the denominators of Equations 3 are direction numbers of L, that is, components of a vector parallel to L.If one of a, b, or c is 0, we can still eliminate t. Forinstance, if a = 0, we could write the equations of L asThis means that L lies in the vertical plane x = x0.1212Equations of Lines and PlanesIn general, we know from Equation 1 that the vector equation of a line through the (tip of the) vector r0 in the direction of a vector v is r = r0 + t v.If the line also passes through (the tip of) r1, then we can take v = r1 – r0 and so its vector equation is r = r0 + t(r1 – r0) = (1 – t)r0 + tr1The line segment from r0 to r1 is given by the parameter interval 0  t  1.1313Planes1414PlanesAlthough a line in space is determined by a point and a direction, a plane in space is more difficult to describe.A single vector parallel to a plane is not enough to convey the “direction” of the plane, but a vector perpendicular to the plane does completely specify its direction.Thus a plane in space is determined by a point P0(x0, y0, z0) in the plane and a vector n that is orthogonal to the plane.This orthogonal vector n is called a normal vector.1515PlanesLet P(x, y, z) be an arbitrary point in the plane, and let r0 and r be the position vectors of P0 and P.Then the vector r – r0 is represented by (See See figure 6.Figure 61616PlanesThe normal vector n is orthogonal to every vector in the given plane. In particular, n is orthogonal to r – r0 and so we havewhich can be rewritten asEither Equation 5 or Equation 6 is called a vector equation of the plane.1717PlanesTo obtain a scalar equation for the plane, we writen = a, b, c, r = x, y, z, and r0 = x0, y0, z0. Then the vector equation becomesa, b, c • x – x0, y – y0, z – z0 = 0orEquation 7 is the scalar equation of the plane through P0(x0, y0, z0) with normal vector n = a, b, c.1818PlanesBy collecting terms in Equation 7, we can rewrite the equation of a plane aswhere d = –(ax0 + by0 + cz0).Equation 8 is called a linear equation in x, y, and z. Conversely, it can be shown that if a, b, and c are not all 0, then the linear equation represents a plane with normal vector a, b, c.1919PlanesTwo planes are parallel if their normal vectors are parallel.For instance, the planes x + 2y – 3z = 4 and 2x + 4y – 6z = 3 are parallel because their normal vectors are n1 = 1, 2, –3 and n2 = 2, 4, –6 and n2 = 2n1.If two planes are not parallel,then they intersect in a straight line and the angle between the two planes is defined as the acute angle between their normal vectors (the angle  in Figure 9).(Review Section 12.3 for angles and the dot product.)Figure


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UIUC MATH 241 - 12_05

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