KIN 3309 1nd Edition Lecture 9 Outline of Last Lecture I. Human Movement AnalysisII. KinematicsIII. Linear KinematicsIV. Collection of Kinematic DataV. Spatial Reference SystemsVI. Cartesian Coordinate SystemVII. 2-D Cartesian Coordinate SystemVIII. Two-Dimensional Reference SystemIX. Quadrants in a Two-Dimensional Reference SystemX. Three-Dimensional Reference SystemXI. Three-Dimensional Coordinate SystemXII. Vectors and ScalarsXIII. Vector MagnitudeXIV. Distance from OriginXV. Vector ComponentsXVI. Vector DirectionXVII. Vector OrientationXVIII. Vector Orientation StandardXIX. Vector Arithmetic XX. Example 1aXXI. Example 1bXXII. Example 1cXXIII. Example 1dXXIV. Example 2aXXV. Example 2bXXVI. Example 2cXXVII. Example 3XXVIII. Example 4XXIX. Position and DisplacementXXX. Example 5XXXI. QuizOutline of Current Lecture These notes represent a detailed interpretation of the professor’s lecture. GradeBuddy is best used as a supplement to your own notes, not as a substitute.I.Current Lecture*Constant Velocity: the xf is very importantI. Quiza. A sprinter is observed to run 50 meters in 7.5 seconds. Calculate the speed of thesprinter in m/sec.i. 50 m / 7.5 s = 6.67 m/sb. An individual runs 20 km in 89 minutes. What was the average speed in meters per second?i. 0.27ii. 0.90iii. 3.75: 20/89 = 0.23 km / min then .23x (1000/60) = 3.75 m/siv. 225c. During running 100 m, a runner runs from the 20- to 30- meter mark in 60 frames of a video record. If the video camera recorded data at 50 fps, how fast was she running during this interval?i. 6.5 m/sii. 36 m/siii. 8.3 m/siv. 0.167 m/sd. A sprinter moving in a straight line at constant velocity starts at a position of 10 meters and finishes at 30 meters in five seconds. What is the velocity of the car inmeters per second?i. 4ii. 6iii. 8iv. 2e. During the end of a 100-m race, a runners acceleration is negative. Which statement accurately interprets this observation?i. The runner is slowing down while moving in the positive direction.ii. The runner is speeding up while moving in the negative direction.iii. The slope of the velocity versus time plot is positive.iv. The runner is slowing down while moving in the negative direction.v. Acceleration is negative, velocity is negative or constantf. A bobsled accelerates from rest at a constant rage of 3 m/s2. How fast is it going after 3.5 seconds?i. 6.5 m/sii. 7 m/siii. 9 m/siv. 10.5 m/sg. A triple jumper needs a velocity of 9.2 m/s to make a good jump. If he is accelerating at 1.65 m/s2, how much time does he need to reach the velocity?i. 4.58 sii. 5.71 siii. 3.5 siv. 5.58 sh. A soccer ball is rolling with a constant acceleration (a) of -0.5 m/s2. At ti = 0 s, theball has an instantaneous velocity of 6 m/s (vi). After 3 s (tf) of rolling, what would be the velocity (vf) of the ball?i. 7.5 m/sii. -0.5 m/siii. 5.5 m/siv. 4.5
View Full Document
Unlocking...