25/25 points Last Response | Show Details All Responses Notes During your In Lab assignment, you prepared a reaction table for Solution #1B. Now you will make similar reaction tables for Solutions #2B - #5B.1. From your Data Table B, enter the equilibrium concentrations of FeSCN2+ you calculated for each of the following solutions. Solution # Calculated Equilibrium [FeSCN2+] (M)2B7.25e-05 [7.25e-05]3B5.51e-05 [5.51e-05]4B0.000118 [0.000118]5B9.14e-05 [9.14e-05]2. Complete the reaction table for Solution 2B below. All entries should be in molarity.Fe3+(aq) + SCN1-(aq) FeSCN2+(aq)[initial]0.000667 [0.000667]0.00100 [0.00100]0.00 [0.00][ ]-7.25e-05 [-7.25e-05]-7.25e-5 [-7.25e-05]7.25e-5 [7.25e-05][final]0.000595 [0.000595]0.00093 [0.00093]7.25e-5 [7.25e-05]3. Complete the reaction table for Solution 3B below. All entries should be in molarity.Fe3+(aq) + SCN1-(aq) FeSCN2+(aq)[initial]0.00100 [0.00100]0.00100 [0.00100]0.00 [0.00][ ]-5.51e-5 [-5.51e-05]-5.51e-5 [-5.51e-05]5.51e-5 [5.51e-05][final]0.00094 [0.00094]0.00094 [0.00094]5.51e-5 [5.51e-05]4. Complete the reaction table for Solution 4B below. All entries should be in molarity.Fe3+(aq) + SCN1-(aq) FeSCN2+(aq)[initial]0.00100 [0.00100 0.000667 [0.0006 0.00 [0.00]] 67][ ]-1.18e-4 [-0.000118]-1.18e-4 [-0.000118]1.18e-4[0.000118][final]0.00088 [0.00088]0.000549 [0.000549]1.18e-4[0.000118]5. Complete the reaction table for Solution 5B below. All entries should be in molarity.Fe3+(aq) + SCN1-(aq) FeSCN2+(aq)[initial]0.00100 [0.00100]0.000333 [0.000333]0.00 [0.00][ ]-9.14e-5 [-9.14e-05]-9.14e-5 [-9.14e-05]9.14e-5 [9.14e-05][final]0.00091 [0.00091]0.000242 [0.000242]9.14e-5 [9.14e-05]6. Calculate the equilibrium constant for this reaction based on each solution andenter your results in the table below. (Please enter your Solution #1B result from your In Lab assignment too.) Solution # Calculated Equilibrium Constant (K)1B250 [250]2B130 [130]3B62 [62]4B240 [240]5B420 [420]7. Calculate the average equilibrium constant for this reaction based on your calculations from Solutions #1B - #5B. K = 220 [220]8. Based on your result for the equilibrium constant of this reaction, select all of the following that are correct about the reaction. [_] [_] H° is greater than zero [_] [_] H° is less than zero [_] [_] H° is equal to zero [x] [x] the sign on H° cannot be determined from K [_] [_] G° is greater than zero[x] [x] G° is less than zero [_] [_] G° is equal to zero [_] [_] the sign on G° cannot be determined from K [x] [x] the reaction is extensive [_] [_] the reaction is not extensive [_] [_] it cannot be determined if the reaction is extensive or not based on
View Full Document
Unlocking...