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NCSU CH 202 - Lab 05 In Lab

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1. 30/30 points Last Response | Show Details All Responses Notes Data Table A. Calibration Curve of FeSCN2+ SolutionsSolution#Volumeof0.100 M Fe3+ (mL)Volume of 5.00x10-4 M SCN1- (mL)Volume ofwater (mL)Total Volume(mL)[FeSCN2+](M)Absorbance at 477 nmBlank 1.00 0.00 5.00 6.00 ------- -------1A 1.00 1.00 4.00 6.008.33e-5 [8.33e-05].296 [0.296]2A 1.00 1.50 3.50 6.00.000125 [0.000125].440 [0.440]3A 1.00 2.00 3.00 6.00.000167 [0.000167].586 [0.586]4A 1.00 2.50 2.50 6.00.000208 [0.000208].708 [0.708]5A 1.00 3.00 2.00 6.00.000250 [0.000250].855 [0.855]Equation of Trendliney = 3330 [3330]x+ .0187 [0.0187] R2 = 1.00[1.00]Question 3a. In Part A, how does the intenstiy of the color of the solutions vary with the concentration of FeSCN2+ in solution? (_) (_) as the [FeSCN2+] decreases, the solution becomes more red (o) (o) as the [FeSCN2+] increases, the solution becomes more red (_) (_) the color of the solutions do not vary with the [FeSCN2+] (_) (_) the [FeSCN2+] is the same for all the solutions so the intensity of thecolor doesn't change (_) (_) cannot tell from the information given Question 3b. In Part A, how does the absorbance of the solutions vary with the concentration of FeSCN2+ in solution? (_) (_) as the [FeSCN2+] increases, the absorbance decreases (o) (o) as the [FeSCN2+] increases, the absorbance increases (_) (_) the absorbance of the solutions do not vary with the [FeSCN2+](_) (_) the [FeSCN2+] does not change so the absorbances are all the same (_) (_) cannot tell from the information given Data Table B. Measuring [FeSCN2+] in Equilibrium MixturesSolution #Volume of2.00x10-3 MFe3+(mL)Volume of2.00x10-3 M SCN1-(mL)Volume of water(mL)Total Volume(mL)Initial[Fe3+](M)Initial[SCN1-](M)Absorbance at 477nmCalculatedEquilibrium [FeSCN2+] (M)1B 1.00 3.00 2.00 6.003.33e-4[0.000333]1.00e-3[0.00100].230[0.230]6.35e-5[6.35e-05]2B 2.00 3.00 1.00 6.006.67e-4[0.000667]1.00e-3[0.00100].260[0.260]7.25e-5[7.25e-05]3B 3.00 3.00 0.00 6.001.00e-3[0.00100]1.00e-3[0.00100].202[0.202]5.51e-5[5.50e-05]4B 3.00 2.00 1.00 6.001.00e-3[0.00100]6.67e-4[0.000667].413[0.413]1.18e-4[0.000118]5B 3.00 1.00 2.00 6.001.00e-3[0.00100]3.33e-4[0.000333].323[0.323]9.14e-5[9.14e-05]Question 7. Complete the reaction table for Solution 1B below. All entries should be in molarity.Fe3+(aq) + SCN1-(aq) FeSCN2+(aq)[initial]3.33e-4[0.000333]1.00e-3[0.00100]0.00 [0.00][ ]-6.35e-5 [- -6.35e-5 [- 6.35e-5 [6.35e-6.35e-05] 6.35e-05] 05][final]2.70e-4[0.000270]9.4e-4[0.00094]6.35e-5 [6.35e-05]Question 8. From the equilibrium concentrations in the table for Solution 1B above, calcualte the equilibrium constant for the reaction. K = 250 [250]2. 5/5 points Last Response | Show Details All Responses Notes Type the title of your graph in the answer box. Your instructor will enter the score for your graph in the score box for this question. Make sure you turn in a copy of your graph before leaving lab! Concentration as a function of absorbanceKey: Enter the score for this student's graph here if lower than full credit. Check for title, labels, trendline and equation.3. 15/15 points Last Response | Show Details All Responses Notes Type your name in the answer box. Your instructor will enter your discretionary lab grade in the score box for this question. AMIT PATELKey: Enter a discretionary score for this student, if lower than full


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NCSU CH 202 - Lab 05 In Lab

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