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NCSU CH 202 - Lab 03 In Lab

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1. 35/35 points Last Response | Show Details All Responses Notes Data TablesNote: All masses must be reported to three decimal places and all temperatures must be reported to one decimal place.Data Table A. Measuring the Freezing Point of Stearic AcidMass of 30 mL beaker21.176 gMass of 30 mL beaker plus stearic acid30.228 gMass of stearic acid9.052 gMeasured freezing point of stearic acid (first trial)68.3 °CMeasured freezing point of stearic acid (second trial)68.2 °CAverage measured freezing point of stearic acid68.3 °CData Table B. Freezing Point Depression by a Solute, Lauric AcidFirst SolutionSecond SolutionMass of 30 mL beaker and contents30.239g31.275 gMass of 30 mL beaker plus stearic and lauric acids31.273g32.278 gTotal mass of lauric acid1.034 g2.037 gColligative molality (mc) of the solution(Your stearic acid mass from Table A is not accuratePlease use your original beaker tare and the necessary data from Table B).5705 m1.122 mPredicted Tf2.6 °C 5.0 °CTheoretical freezing point of the soltuion(To calculate, use the last entry for your averagefreezing point from Data Table A to the 0.1 C)65.7 °C63.3 °CMeasured freezing point of the solution65.0 °C62.4 °CIn-Lab QuestionsQuestion 1 In Part B for the first solution made by adding lauric acid, did you expect the freezing point to be at a higher or lower temperature thatn that of the pure solvent, stearic acid?(_) higher (o) lower (_) the same (_) cannot predict from the information given Question 3a In Part B for the first solution made by adding lauric acid, how did your measured freezing point compare to your theoretical freezingpoint? (_) measured was higher (o) measured was lower (_) they were the same (_) cannot predict from the information given Question 3b In Part B for the first solution made by adding lauric acid, calculate the % difference. The equation for percent difference is: % difference = ((theoretical value - actual value) x 100%) / theoretical value. A percent difference can be positive or negative.% Difference = 1.07Question 4 In Part B for the second solution made by adding lauric acid, did you expect the freezing point to be at a higher or lower temperature thatn that of the pure solvent, stearic acid?(_) higher (o) lower (_) the same (_) cannot predict from the information given Question 6a In Part B for the second solution made by adding lauric acid, how did your measured freezing point compare to your theoretical freezingpoint? (_) measured was higher (o) measured was lower (_) they were the same (_) cannot predict from the information given Question 6b In Part B for the second solution made by adding lauric acid,calculate the % difference. The equation for percent difference is: % difference = ((theoretical value - actual value) x 100%) / theoretical value.A percent difference can be positive or negative.% Difference = 1.422. 15/15 points Last Response | Show Details All Responses Notes Type your name in the answer box. Your instructor will enter your discretionary lab grade in the score box for this question. Amit


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NCSU CH 202 - Lab 03 In Lab

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