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NCSU CH 202 - Lab 06 In Lab

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1. 35/35 points Last Response | Show Details All Responses Notes Data Table A. Calculated and Measured pH's of Acid and Base MixturesReaction # Reagents Calculated pH Measured pH110 mL H2O7.00 [7.00] 6.66 [6.66]+ 5 mL NaOH12.52 [12.52] 11.77 [11.77]+ additional 5 mL NaOH12.70 [12.70] 12.02 [12.02]+ additional 5 mL NaOH12.79 [12.78] 12.10 [12.10]210 mL HCl1.00 [1.00] 1.55 [1.55]+ 5 mL NaOH1.48 [1.48] 1.67 [1.67]+ additional 5 mL NaOH7.00 [7.00] 2.14 [2.14]+ additional 5 mL NaOH12.30 [12.30] 11.51 [11.51]310mL NH4Cl5.13 [5.13] 6.78 [6.78]+ 5 mL NaOH See question 4c.9.11 [9.11]+ additional 5 mL NaOH --------9.89 [9.89]+ additional 5 mL NaOH --------11.63 [11.63]410 mL NaC2H3O28.87 [8.87] 9.19 [9.19]+ 5 mL NaOH See question 6c.11.88 [11.88]+ additional 5 mL NaOH --------12.04 [12.04]+ additional 5 mL NaOH --------12.12 [12.12]Question 4a. Complete the reaction table for the mixture of 10.0 mL of 0.10 M NH4Cl with 5.0 mL of 0.10 M NaOH below. All entries should be in millimoles. Report all values to one decimal place.NH41+(aq) + OH1-(aq) NH3(aq) + H2Oinitial1.0 [1.0] .5 [0.5] 0 [0]-.5 [-0.5] -.5 [-0.5] .5 [0.5]final.5 [0.5] 0 [0] .5 [0.5]Question 4b. Calculate the equilibrium concentrations of each of the following in the resulting solution. Report all values to two signigicant figures.Species Final Concentration (M)[NH41+].033 [0.033][OH1-]1.8e-5 [1.8e-05][NH3].033 [0.033][H3O1+]5.6e-10 [5.6e-10]Question 4c. Based on your results above and using the Henderson-Hasselbalch equation, calculate the pH of this solution to two decimal places. pH = 9.25 [9.25]Question 6a. For the mixture of 10.0 mL of 0.10 M NaC2H3O2 with 5.0 mL of 0.10M NaOH, which of the following is true? (_) (_) this reaction goes to completion and NaC2H3O2 is the limiting reagent (_) (_) this reaction goes to completion and NaOH is the limiting reagent (_) (_) this reaction does not go to completion but is described by the Kb for C2H3O21- (o) (o) there is no net reaction between NaC2H3O2 and NaOH Question 6b. For the mixture of 10.0 mL of 0.10 M NaC2H3O2 with 5.0 mL of 0.10 M NaOH, calculate the equilibrium concentrations of each of the following in the resulting solution. Report all values to two signigicant figures.Species Final Concentration (M)[C2H3O21-].066 [0.067][HC2H3O2](tricky)0 [0.0][OH1-].033 [0.033][H3O1+]3.0e-13 [3.0e-13]Question 6c. Based on your results above, calculate the pH of this solution to two decimal places. pH = 12.52 [12.52]2. 15/15 points Last Response | Show Details All Responses Notes Type your name in the answer box. Your instructor will enter your discretionary lab grade in the score box for this question. Amit PatelKey: Enter a discretionary score for this student, if lower than full


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NCSU CH 202 - Lab 06 In Lab

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