Pre-Lab Questions1. In one of your experiments, you will roll a marble down a ramp to provide an initial horizontal velocity. Suppose you start the marble at rest (vo = 0 m/s) and it travels a distance of, d, down the ramp. Use 1-D kinematics to predict the velocity of the ball (vf ) at the bottom of the ramp. Hint: the acceleration of the ball down the ramp is 9.81*sin(θ) m/s2 where θ is the angle of the ramp. Record you answer in variables(you will calculate the velocity with magnitudes when you perform the experiment).From law of conservation of energy: Energy at top is equal to the energy at the bottomVo = 0 m/sAngle of ramp is theta acceleration a = g * sin(θ)Third equation of motionVf2 – uo2 = 2 * a * dVf2= 2 * 9.81 * sin(θ)*dVf = 4.43 * sqrt(d * sin(θ))2. Use the kinematic equations to derive a general equation for the time it takes a ball dropped from rest at vertical height, h, to reach the ground.Second equation of motionh = u * t + 0.5 * a * t2h = 0.5 * g * t2t = sqrt(2*h/g)© 2014 eScience Labs, LLC.All Rights Reserved3. Use the result from Question 2 to write a general equation for the distance travelled by a projectile that is rolling of a table of height, h, with a horizontal speed, v0x.Distance travelled = t * V0xDistance travelled = sqrt(2*h/g)* V0x4. The range of projectiles is dependent on the velocity and angle of the launch. Use the kinematic equations to show the range of a projectile launched at velocity, v, and angle, θ, is equal to Hint: The velocity at the beginning and end of the motion has the same magnitude, butopposite direction.Range = V0x * time of flight=V* cos(theta) * 2*v*sin(theta)/g=2V2 * sin(theta) * cos(theta)/g=V2 * sin(2*theta)/g© 2014 eScience Labs, LLC.All Rights
View Full Document
Unlocking...