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Penn CIT 594 - Priority Queues

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Priority QueuesPriority queueA priority queue ADTEvaluating implementationsArray implementationsLinked list implementationsBinary tree implementationsHeap implementationArray representation of a heapUsing the heapCommentsJava 5 java.util.PriorityQueueThe EndPriority Queues2Priority queueA stack is first in, last outA queue is first in, first outA priority queue is least-first-outThe “smallest” element is the first one removed(You could also define a largest-first-out priority queue)The definition of “smallest” is up to the programmer (for example, you might define it by implementing Comparator or Comparable)If there are several “smallest” elements, the implementer must decide which to remove firstRemove any “smallest” element (don’t care which)Remove the first one added3A priority queue ADTHere is one possible ADT:PriorityQueue(): a constructorvoid add(Comparable o): inserts o into the priority queueComparable removeLeast(): removes and returns the least elementComparable getLeast(): returns (but does not remove) the least elementboolean isEmpty(): returns true iff emptyint size(): returns the number of elementsvoid clear(): discards all elements4Evaluating implementationsWhen we choose a data structure, it is important to look at usage patternsIf we load an array once and do thousands of searches on it, we want to make searching fast—so we would probably sort the arrayIf we load a huge array and expect to do only a few searches, we probably don’t want to spend time sorting the arrayFor almost all uses of a queue (including a priority queue), we eventually remove everything that we addHence, when we analyze a priority queue, neither “add” nor “remove” is more important—we need to look at the timing for “add + remove”5Array implementationsA priority queue could be implemented as an unsorted array (with a count of elements)Adding an element would take O(1) time (why?)Removing an element would take O(n) time (why?)Hence, adding and removing an element takes O(n) timeThis is an inefficient representationA priority queue could be implemented as a sorted array (again, with a count of elements)Adding an element would take O(n) time (why?)Removing an element would take O(1) time (why?)Hence, adding and removing an element takes O(n) timeAgain, this is inefficient6Linked list implementationsA priority queue could be implemented as an unsorted linked listAdding an element would take O(1) time (why?)Removing an element would take O(n) time (why?)A priority queue could be implemented as a sorted linked listAdding an element would take O(n) time (why?)Removing an element would take O(1) time (why?)As with array representations, adding and removing an element takes O(n) timeAgain, these are inefficient implementations7Binary tree implementationsA priority queue could be represented as a (not necessarily balanced) binary search treeInsertion times would range from O(log n) to O(n) (why?)Removal times would range from O(log n) to O(n) (why?)A priority queue could be represented as a balanced binary search treeInsertion and removal could destroy the balanceWe need an algorithm to rebalance the binary treeGood rebalancing algorithms require only O(log n) time, but are complicated8Heap implementationA priority queue can be implemented as a heapIn order to do this, we have to define the heap propertyIn Heapsort, a node has the heap property if it is at least as large as its childrenFor a priority queue, we will define a node to have the heap property if it is as least as small as its children (since we are using smaller numbers to represent higher priorities)128 3Heapsort: Blue node has the heap property38 12Priority queue: Blue node has the heap property9Array representation of a heapLeft child of node i is 2*i + 1, right child is 2*i + 2Unless the computation yields a value larger than lastIndex, in which case there is no such childParent of node i is (i – 1)/2Unless i == 01214186833 12 6 18 14 8 0 1 2 3 4 5 6 7 8 9 10 11 12lastIndex = 510Using the heapTo add an element:Increase lastIndex and put the new value thereReheap the newly added nodeThis is called up-heap bubbling or percolating upUp-heap bubbling requires O(log n) timeTo remove an element:Remove the element at location 0Move the element at location lastIndex to location 0, and decrement lastIndex Reheap the new root node (the one now at location 0)This is called down-heap bubbling or percolating downDown-heap bubbling requires O(log n) timeThus, it requires O(log n) time to add and remove an element11CommentsA priority queue is a data structure that is designed to return elements in order of priorityEfficiency is usually measured as the sum of the time it takes to add and to remove an elementSimple implementations take O(n) timeHeap implementations take O(log n) timeBalanced binary tree implementations take O(log n) timeBinary tree implementations, without regard to balance, can take O(n) (linear) timeThus, for any sort of heavy-duty use, heap or balanced binary tree implementations are better12Java 5 java.util.PriorityQueueJava 5 finally has a PriorityQueue class, based on heapsPriorityQueue<E> queue = new PriorityQueue<E>();boolean add(E o)boolean remove(Object o)boolean offer(E o)E peek()boolean poll()void clear()int size()13The


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Penn CIT 594 - Priority Queues

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