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UW-Madison PHYSICS 207 - Lecture 11

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Physics 207, Lecture 11, Oct. 8Locomotion: how fast can a biped walk?How fast can a biped walk?Slide 4Slide 5Slide 6Slide 7Slide 8Slide 9Orbiting satellites vT = (gr)½Geostationary orbitSlide 12Impulse & Linear MomentumForces vs time (and space, Ch. 10)Example 1Twice the massExample 1Slide 18Force curves are usually a bit different in the real worldExample 1 with Action-ReactionSlide 21Slide 22Applications of Momentum ConservationSlide 24Momentum ConservationSlide 26Exercise 1 Momentum is a Vector (!) quantitySlide 28Slide 29Inelastic collision in 1-D: Example 2Example 2 Inelastic Collision in 1-D with numbersExercise 2 Momentum ConservationPhysics 207, Oct. 8Physics 207: Lecture 11, Pg 1Physics 207, Lecture 11, Oct. 8Goals:Goals:Assignment:Assignment:Monday, Read through Chapter 10 (1st half)MP HW5, due Wednesday 10/15 • Chapter 9: Momentum & ImpulseChapter 9: Momentum & Impulse Understand what momentum is and how it relates to forces Employ momentum conservation principles  In problems with 1D and 2D Collisions  In problems having an impulse (Force vs. time) Chapter 8: Use models with free fallPhysics 207: Lecture 11, Pg 2Locomotion: how fast can a biped walk?Physics 207: Lecture 11, Pg 3How fast can a biped walk?What about weight?(a) A heavier person of equal height and proportions can walk faster than a lighter person(b) A lighter person of equal height and proportions can walk faster than a heavier person(c) To first order, size doesn’t matterPhysics 207: Lecture 11, Pg 4How fast can a biped walk?What about height?(a) A taller person of equal weight and proportions can walk faster than a shorter person(b) A shorter person of equal weight and proportions can walk faster than a taller person(c) To first order, height doesn’t matterPhysics 207: Lecture 11, Pg 5How fast can a biped walk?What can we say about the walker’s acceleration if there is UCM (a smooth walker) ?Acceleration is radial !So where does it, ar, come from?(i.e., what external forces are on the walker?)1. Weight of walker, downwards2. Friction with the ground, sidewaysPhysics 207: Lecture 11, Pg 6How fast can a biped walk?What can we say about the walker’s acceleration if there is UCM (a smooth walker) ?Acceleration is radial !So where does it, ar, come from?(i.e., what external forces are on the walker?)1. Weight of walker, downwards2. Friction with the ground, sidewaysPhysics 207: Lecture 11, Pg 7How fast can a biped walk?What can we say about the walker’s acceleration if there is UCM (a smooth walker) ?Acceleration is radial !So where does it, ar, come from?(i.e., what external forces are on the walker?)1. Weight of walker, downwards2. Friction with the ground, sideways(most likely from back foot)3. Need a normal force as wellPhysics 207: Lecture 11, Pg 8How fast can a biped walk?What can we say about the walker’s acceleration if there is UCM (a smooth walker) ?Acceleration is radial !So where does it, ar, come from?(i.e., what external forces are on the walker?)1. Weight of walker, downwards2. Friction with the ground, sideways(Notice the new direction)Physics 207: Lecture 11, Pg 9How fast can a biped walk?Given a model then what does the physics say?Choose a position with the simplest constraints.If his radial acceleration is greater than g then he is “in orbit”Fr = m ar = m v2 / r < mgOtherwise you will lose contact!ar = v2 / r  vmax = (gr)½ vmax ~ 3 m/s !(And it pays to be tall and live on Jupiter)Physics 207: Lecture 11, Pg 10Orbiting satellites vT = (gr)½Physics 207: Lecture 11, Pg 11Geostationary orbitPhysics 207: Lecture 11, Pg 12Geostationary orbitThe radius of the Earth is ~6000 km but at 36000 km you are ~42000 km from the center of the earth. Fgravity is proportional to r-2 and so little g is now ~10 m/s2 / 50 vT = (0.20 * 42000000)½ m/s = 3000 m/s At 3000 m/s, period T = 2 r / vT = 2 42000000 / 3000 sec = = 90000 sec = 90000 s/ 3600 s/hr = 24 hrs Orbit affected by the moon and also the Earth’s mass is inhomogeneous (not perfectly geostationary) Great for communication satellites (1st pointed out by Arthur C. Clarke)Physics 207: Lecture 11, Pg 13Impulse & Linear MomentumTransition from forces to conservation lawsNewton’s Laws  Conservation LawsConservation Laws  Newton’s Laws They are different faces of the same physics NOTE: We have studied “impulse” and “momentum” but we have not explicitly named them as suchConservation of momentum is far more general thanconservation of mechanical energyPhysics 207: Lecture 11, Pg 14Forces vs time (and space, Ch. 10)Underlying any “new” concept in Chapter 9 is (1) A net force changes velocity (either magnitude or direction) (2) For any action there is an equal and opposite reactionIf we emphasize Newton’s 3rd Law and look at the changes with time then this leads to the Conservation of Momentum PrinciplePhysics 207: Lecture 11, Pg 15Example 1A 2 kg block, initially at rest on frictionless horizontal surface, is acted on by a 10 N horizontal force for 2 seconds (in 1D).What is the final velocity?F is to the positive & F = ma thus a = F/m = 5 m/s2 v = v0 + a t = 0 m/s + 2 x 5 m/s = 10 m/s (+ direction)Notice: v - v0 = a t  m (v - v0) = ma t  m v = F t If the mass had been 4 kg … now what final velocity?F-+F (N)1002time (s)Physics 207: Lecture 11, Pg 16Twice the massSame forceSame timeHalf the acceleration (a = F / m’) Half the velocity ! ( 5 m/s )F (N)1002Time (sec)FBeforePhysics 207: Lecture 11, Pg 17Example 1 Notice that the final velocity in this case is inversely proportional to the mass (i.e., if thrice the mass….one-third the velocity). Here, mass times the velocity always gives the same value. (Always 20 kg m/s.)F (N)1002Time (sec)Area under curve is still the same !Force x change in time = mass x change in velocityPhysics 207: Lecture 11, Pg 18Example 1 There many situations in which the sum of the products “mass times velocity” is constant over time To each product we assign the name, “momentum” and associate it with a conservation law. (Units: kg m/s or N s)A force applied for a certain period of time can be graphed and the area under the curve is the “impulse” F (N)1002Time (sec)Area under curve : “impulse”With: m v = Favg tPhysics 207: Lecture 11, Pg 19Force curves are usually a bit different in the real worldPhysics


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UW-Madison PHYSICS 207 - Lecture 11

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