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UW-Madison PHYSICS 207 - Lecture 15 Notes

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Lecture 15Scalar Product (or Dot Product)Work in terms of the dot productEnergy and WorkSlide 7Exercise Work in the presence of friction and non-contact forcesWork and Varying Forces (1D)Slide 10Slide 11Conservative Forces & Potential EnergyConservative Forces and Potential EnergyExercise Work Done by GravityA Non-Conservative ForceWork & Power:Slide 21Slide 22Exercise Work & PowerChap. 12: Rotational DynamicsRotational VariablesRotational Variables...Slide 28Physics 207: Lecture 15, Pg 1Lecture 15Goals:Goals:•Chapter 11Chapter 11 Employ the dot product Employ conservative and non-conservative forces Use the concept of power (i.e., energy per time)•Chapter 12Chapter 12 Extend the particle model to rigid-bodies Understand the equilibrium of an extended object. Understand rigid object rotation about a fixed axis. Employ “conservation of angular momentum” conceptAssignment: HW7 due March 10th For Thursday: Read Chapter 12, Sections 7-11do not concern yourself with the integration process in regards to “center of mass” or “moment of inertia””Physics 207: Lecture 15, Pg 2Useful for finding parallel componentsA - î = Axî - î = 1 î - ĵ = 0A - B = (Ax )(Bx) + (Ay )(By ) + (Az )(Bz )Calculation can be made in terms of components.Calculation also in terms of magnitudes and relative angles.Scalar Product (or Dot Product)A - B ≡ | A | | B | cos You choose the way that works best for you!cosBABA-îAAxAyĵPhysics 207: Lecture 15, Pg 4Work in terms of the dot productIngredients: Force ( F ), displacement (  r )Looks just like a Dot Product! rdisplacementFWork, W, of a constant force F acts through a displacement  r :If the path is curved at each pointand rdFdWrdFfirrrdFWrFrFW-cosPhysics 207: Lecture 15, Pg 6Energy and WorkWork, W, is the process of energy transfer in which a force component parallel to the path acts over a distance; individually it effects a change in energy of the “system”.1. K or Kinetic Energy 2. U or Potential Energy (Conservative)and if there are losses (e.g., friction, non-conservative)3. ETh Thermal EnergyPositive W if energy transferred to a systemPhysics 207: Lecture 15, Pg 7A. U  K B. U  EThC. K  UD. K EThE. There is no transformation because energy is conserved.A child slides down a playground slide at constant speed. The energy transformation isPhysics 207: Lecture 15, Pg 8ExerciseWork in the presence of friction and non-contact forcesA. 2B. 3C. 4D. 5A box is pulled up a rough ( > 0) incline by a rope-pulley-weight arrangement as shown below. How many forces (including non-contact ones) are doing work on the box ? Of these which are positive and which are negative? State the system (here, just the box) Use a Free Body Diagram Compare force and path vPhysics 207: Lecture 15, Pg 9Work and Varying Forces (1D)Consider a varying force F(x)FxxxArea = Fx xF is increasingHere W = F · r becomes dW = Fx dx F = 0° StartFinishWork has units of energy and is a scalar!fixxxdxxFW )(FxPhysics 207: Lecture 15, Pg 10•How much will the spring compress (i.e. x = xf - xi) to bring the box to a stop (i.e., v = 0 ) if the object is moving initially at a constant velocity (vi) on frictionless surface as shown below with xi = xeq , the equilibrium position of the spring?xvimtiFspring compressedspring at an equilibrium positionV=0tmfixxxdxxFW )(boxfixxeqdxxxkW )(-boxfiixxxxkW|221box)( - K 0 )( -221221box kxxkifW2i212 21221v0 - mmxk Example: Hooke’s Law Spring (xi equilibrium)Physics 207: Lecture 15, Pg 11Work signsxvimtiFspring compressedspring at an equilibrium positionV=0tmNotice that the spring force is opposite the displacementFor the mass m, work is negativeFor the spring, work is positive They are opposite, and equal (spring is conservative)Physics 207: Lecture 15, Pg 12Conservative Forces & Potential EnergyFor any conservative force F we can define a potential energy function U in the following way:The work done by a conservative force is equal and opposite to the change in the potential energy function.W = F ·dr ≡ - U rirf Uf UiPhysics 207: Lecture 15, Pg 13Conservative Forces and Potential EnergySo we can also describe work and changes in potential energy (for conservative forces)U = - WRecalling (if 1D)W = Fx xCombining these two,U = - Fx xLetting small quantities go to infinitesimals,dU = - Fx dxOr,Fx = -dU / dxPhysics 207: Lecture 15, Pg 14 ExerciseWork Done by GravityAn frictionless track is at an angle of 30° with respect to the horizontal. A cart (mass 1 kg) is released from rest. It slides 1 meter downwards along the track bounces and then slides upwards to its original position. How much total work is done by gravity on the cart when it reaches its original position? (g = 10 m/s2)1 meter30°(A) 5 J (B) 10 J (C) 20 J (D) 0 J h = 1 m sin 30° = 0.5 mPhysics 207: Lecture 15, Pg 19A Non-Conservative ForcePath 2Path 1Since path2 distance >path1 distance the puck will be traveling slower at the end of path 2. Work done by a non-conservative force irreversibly removes energy out of the “system”. Here WNC = Efinal - Einitial < 0  and reflects EthermalPhysics 207: Lecture 15, Pg 20Work & Power:Two cars go up a hill, a Corvette and a ordinary Chevy Malibu. Both cars have the same mass. Assuming identical friction, both engines do the same amount of work to get up the hill.Are the cars essentially the same ?NO. The Corvette can get up the hill quickerIt has a more powerful engine.Physics 207: Lecture 15, Pg 21Work & Power:Power is the rate at which work is done.InstantaneousPower:AveragePower:A person, mass 80.0 kg, runs up 2 floors (8.0 m). If they climb it in 5.0 sec, what is the average power used?Pavg = F h / t = mgh /  t = 80.0 x 9.80 x 8.0 / 5.0 WP = 1250 W Example:Units (SI) areWatts (W):1 W = 1 J / 1stWPdtdWP Physics 207: Lecture 15, Pg 22Work & Power:Power is also,If force constant, W= F x = F ( v0 t + ½ at2 )and P = W / t = F (v0 + at) xxxvFPtxFtWP Physics 207: Lecture 15, Pg 23Exercise Work & PowerA. TopB. MiddleC. BottomStarting from rest, a car drives up a hill at constant acceleration and then quickly stops at the


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UW-Madison PHYSICS 207 - Lecture 15 Notes

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