Exam III review.RII-1 How many ohms in a coulomb?A) one gazillion B) one coullion C) 17D) None of theseRII-2Does the capacitance of a capacitor depend on the charge Q on the capacitor?A) Yes B) No C) Depends on the type of capacitor.RII-3A capacitor is attached to a battery which maintains a constant voltage V across the capacitor plates. While the battery is attached, the plates are moved further apart. The energy stored in the capacitor..A) increased.B) decreased.C) remained constant.Hint: U = (1/2)QV = (1/2)Q2/C = (1/2) CV2 RII-4 A charged capacitor is isolated (so no charge can get on or off). The plates of the capacitor are slowly pulled apart. After the plates are pulled apart a bit, the electric field between the plates A) increased B) decreased C) remained constantThe voltage difference between the plates..A) increased B) decreased C) remained constantThe capacitance ..A) increased B) decreased C) remained constantVRII-5 A parallel-plate capacitor has square plates of edge length L, separated by a distance d. A second capacitor is made with L doubled and d decreased by a factor of 2. By what factor is the capacitance of the new capacitor increased?A) 1 B) 2 C) 4 D) 16 E) None of theseRII-6A copper wire and an aluminum wire both have the same dimensions (same length, same cross-sectional area). Which one statement is true?A) Both wires have the same resistance R and the same resistivity .B) The wires have different resistances and different resistivities.C) The wires have the same resistance but different resistivities.D) The wires have different resistances but the same resistivity.L d LRII-7 Which has higher resistance ? A) 100 W bulb B) 60 W bulb Hint: P = IV = I2R = V2/RRII-8 Consider the following circuit containing three ordinary householdlight bulbs, a 100W light bulb, a 60W bulb, and a 40W bulb. Which one statement is true?A) The 100W bulb will be brightest.B) The 60W bulb will be brightest.C) The 40W bulb will be brightest.D) All the light bulbs glow with the same brightness.RII-9 A 600W hairdryer is attached to 120VAC circuit. What is the peakcurrent through the hairdryer (to within 5%)?A) 10A B) 7A C) 5AHINT: P = IV = I2R = V2/RRII-10The voltage between points a and b in the circuit shown is measured with an ideal voltmeter.What does the voltmeter read? Hint: Recall that an ideal voltmeterhas infinite internal resistance.A) V/2 B) V/3C) V/4 D) zero E) V40W60W100WV R a b R RRII-11 Consider the circuit below. What is the total resistance which thebattery sees?A) 1 B) 2 C) 0.5 D) 0.25 In the circuit above, the resistor R2 is increased to 5. What happens to the current through from the battery?A) increases B) decreases C) remains constantRII-12 In the circuit below which resistors must have the same current flowing through them? Do not assume that the resistors are identical.A) R2 / R5 onlyB) R3/R4 onlyC) R2 / R5 and R3/R4 onlyD) R1/ R2 / R5 onlyWhich resistors have the same voltage drop?A) R2 / R5 onlyB) R3/R4 onlyR2 =2 1 R1 =2 2 1V I=? R4 R2 R1 R3 1V R5C) R2 / R5 and R3/R4 onlyD) R1/ R2 / R5 onlyRII-13 A charged particle is orbiting in a uniform B-field in the sense shown.Is the particle positively or negatively charged?A) positiveB) negativeC) impossible to tell/don't knowRII-14 A coil of wire carrying current I can rotate freely about an axis in a magnetic field. If released from rest in the position shown, which way does it rotate?A) right side will move out of pageB) left side will move out of page.C) loop will not rotate at allB(in) B axis IPOTENTIAL EXAM QUESTIONS:1. Which of the following statements is/are true about the following circuits? Assumeall batteries and all bulbs are identical.a) Bulb A does not turn on, because the voltage difference across it is zero.b) Bulb B does not turn on, because the voltage difference across it is zero.c) Bulb C does not turn on, because the current flowing through it is zero.Answers: (a) is true, (b) is true, (c) is true2. What is the correct order for the total power dissipated in the following circuits, fromleast to greatest? Assume all bulbs and all batteries are identical. Ignore anyinternal resistance of the batteries.a) A < B = C < D < Eb) D < C < B = E < Ac) D < B < E < A < Cd) A = B < D < C < Ee) B < A < C = D < EAnswer: Assume that all bulbs have same resistance R and all batteries have same voltage V. The total resistances are A) 3R, B) R (since 2 of the R are shorted by the wire), C) R, D) R / 3 , E) R.The total voltages are A) V, B) V, C) V (since batteries in parallel), D) V, E) 2V (since batteries inseries).The total power is Ptot = Vtot2 / Rtot A) P = V2 / (3R), B) V2 / R , C) V2 / R , D) V2 / (R / 3) , E) (2V)2 / RSo A < B = C < D <
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