M5 Newton’s Second LawVI. ReportVI(1) l (cm)t1 (s) T12t2 (s) T22t3 (s) T32t4 (s) T42S5.0 0.119 0.014 0.119 0.014 0.123 0.015 0.119 0.011 0.17910.0 0.225 0.050 0.225 0.051 0.225 0.051 0.233 0.054 0.66920.0 0.437 0.191 0.430 0.185 0.434 0.188 0.437 0.191 2.3930.0 0.623 0.388 0.623 0.389 0.634 0.401 0.624 0.389 4.870 0.05 0.1 0.15 0.2 0.25 0.3 0.35 0.4 0.450123456S vs. t2 t2 (s)S The experimentally obtained acceleration is 12.38 ± 0.08. My calculated value of acceleration does not lie within the uncertainty determined from the plot. VI(2) M2 (g) t1 (s) T12t2 (s) T22t3 (s) T32t4 (s) T42α15.6 0.220 0.049 0.221 0.049 0.224 0.050 0.218 0.048 27.4225.6 0.183 0.033 0.184 0.034 0.190 0.036 0.188 0.035 38.5635.6 0.159 0.026 0.159 0.025 0.159 0.025 0.164 0.27 51.8645.6 0.131 0.017 0.134 0.018 0.134 0.018 0.134 0.018 75.1755.6 0.117 0.014 0.118 0.014 0.128 0.017 0.128 0.016 88.9810 15 20 25 30 35 40 45 50 55 60020406080100 vs. M2 αM2 (g) αThe slope of the graph is 1.59 ± 0.11. g= 11.98 ± 0.12. VI(3)My calculated value for a1 =89.5 cm/s2 and for a2 =83.7 cm/s2. The calculated frictionforce is 1538.7 N. This value compared to the value of m2g, is quite larger. VI(4)This experiment could have had some systematic errors. One of which could have been due to the fact that the t values may be off due to the photogate. It may not have been at exactly zero before each time was taken. If this happens some values for t may actually be smaller than was
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