M4 Projectile MotionVI. Report1.)# D(cm)h1(cm)h1Dh2(cm)h2Dh3(cm)h3Dh4(cm)h4Dh5(cm)h5D1 22.1 -5.4 -0.24-6.4 -0.29-6.8 -0.31-6.7 -0.30-6.6 -0.292 27.1 -3.8 -0.14-4.5 -0.17-5.2 -0.19-5.4 -0.19-5.4 -0.193 32.1 -0.6 -0.02-0.6 -0.02-1.3 -0.04-1.2 -0.04-1.5 -0.054 37.1 4.5 0.12 5.1 0.14 5.2 0.14 5.5 0.15 5.1 0.145 42.1 11.6 0.28 11.9 0.28 11.4 0.27 11.9 0.28 12.0 0.296 47.1 18.5 0.39 19.4 0.41 19.0 0.40 19.5 0.41 20.1 0.437 52.1 29.7 0.57 29.0 0.56 29.3 0.56 29.4 0.56 30.3 0.588 57.1 41.4 0.72 42.2 0.74 37.7 0.66 38.6 0.68 36.0 0.632.)3.)The slope of this graph is 0.0285 ±0.0003. The y- intercept is -0.932 ±0.014. e= 137.0158 ±0.0075. m= 128.0 ±0.0. The values do not match with their uncertainties. Though I think that the calculated value should be more accurate. I believe that in this case the measured may be the correct angle. Due to the fact that my partners and I separately all measured the same exact value.4.)v0=212.99± 2.3820 25 30 35 40 45 50 55 60-0.4-0.200.20.40.60.8f(x) = 0.03x − 0.93h/D vs. DD (cm)h/D5.)v0= 217.396.) The v0 from VI-5 almost falls in the range of the determined v0 from VI-6. There couldhave been human error that caused the slight
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