Ce Pr Nd Pm Sm Eu Gd Tb Dy Ho Er Tm Yb LuTh Pa U Np Pu Am Cm Bk Cf Es Fm Md No LrH HeLi Be B C N O F NeNa Mg Al Si P S Cl ArK Ca Sc Ti V Cr Mn Fe Co Ni Cu Zn Ga Ge As Se Br KrRb Sr Y Zr Nb Mo Tc Ru Rh Pd Ag Cd In Sn Sb Te I XeCs Ba La Hf Ta W Re Os Ir Pt Au Hg Tl Pb Bi Po At RnFr Ra Ac Rf Db Sg Bh Hs Mt1 23 4 5 6 7 8 9 1011 12 13 14 15 16 17 1819 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 3637 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 5455 56 57 72 73 74 75 76 77 78 79 80 81 82 83 84 85 8687 88 89 104 105 106 107 108 10958 59 60 61 62 63 64 65 66 67 68 69 70 7190 91 92 93 94 95 96 97 98 99 100 101 102 1031.0079 4.00266.941 9.0122 10.811 12.011 14.0067 15.9994 18.9984 20.179722.9898 24.3050 26.9815 28.0855 30.9738 32.066 35.4527 39.94839.0983 40.078 44.9559 47.88 50.9415 51.9961 54.9380 55.847 58.9332 58.69 63.546 65.39 69.723 72.61 74.9216 78.96 79.904 83.8085.4678 87.62 88.9059 91.224 92.9064 95.94 (98) 101.07 102.9055 106.42 107.8682 112.411 114.82 118.710 121.75 127.60 126.9045 131.39132.9054 137.327 138.9055 178.49 180.9479 183.85 186.207 190.2 192.22 195.08 196.9665 200.59 204.3833 207.2 208.9804 (209) (210) (222)(223) (226) (227) (261) (262) (263) (262) (265) (266)140.115 140.9076 144.24 (145) 150.36 151.965 157.25 158.9253 162.50 164.9303 167.26 168.9342 173.04 174.967232.0381 231.0359 238.0289 (237) (244) (243) (247) (247) (251) (252) (257) (258) (259) (260)1A 8A2A 3A 4A 5A 6A 7A3B 4B 5B 6B 7B 8B 1B 2B1 182 13 14 15 16 173 4 5 6 7 8 9 10 11 12Periodic Table of the ElementsVersion 001 – Exam 1 – David Laude (54705) 2This print-out should have 30 questions.Multiple-choice questions may continue onthe next column or page – find all choicesbefore answering. V1:1, V2:1, V3:1, V4:1,V5:2.ACAMP 02 000108:02, general, multiple choice, > 1 min, fixed.001 (part 1 of 1) 6 pointsA 200 nm photon has how many times theenergy of a 700 nm photon?1. 3.5 correct2. 4.23. 0.294. 0.245. 9.93 × 10−196. 2.84 × 10−19Explanation:Energy of Light: E =hcλFor the 200 nm photon:E =hcλ=(6.626 × 10−34J · s)(3 × 108m · s−1)200 × 10−9m= 9.94 × 10−19JFor the 700 nm photon:E =hcλ=(6.626 × 10−34J · s)(3 × 108m · s−1)700 × 10−9m= 2.84 × 10−19JThus9.94 × 10−19J2.84 × 10−19J= 3.5ChemPrin3e T01 2608:05, general, multiple choice, < 1 min, fixed.002 (part 1 of 1) 6 pointsWhich of the following emission lines corre-sponds to part of the Balmer series of lines inthe spectrum of a hydrogen atom?A) n = 2 → n = 1B) n = 4 → n = 2C) n = 4 → n = 1D) n = 3 → n = 2E) n = 4 → n = 31. B and D only correct2. A, D, and E only3. A and C only4. E only5. B and C only6. D and E only7. B, C, and E onlyExplanation:The Balmer series is produced by elec-tronic transitions which either begin (absorp-tion spectra) or end (emission spectra) at theenergy level n = 2. These correspond mostlyto the visible region.ChemPrin3e 01 3008:05, general, numeric, > 1 min, normal.003 (part 1 of 1) 6 pointsIn the spectrum of atomic hydrogen, a vio-let line is observed at 434 nm. What are thebeginning and ending energy levels of the elec-tron during the emission of energy that leadsto this spectral line?1. n = 5, n = 2 correct2. n = 6, n = 23. n = 6, n = 34. n = 5, n = 35. n = 4, n = 2Version 001 – Exam 1 – David Laude (54705) 36. n = 4, n = 3Explanation:λ = 434 nm = 4.34 × 10−7mBecause the line is in the visible part of thespectrum, it belongs to the Balmer series forwhich the ending n is 2.For the starting value of n,ν =cλ=3 × 108m/s4.34 × 10−7m= 6.909 × 1014s−1Using the Ryberg formula,ν = (3.29 × 1015s−1)µ1n22−1n21¶ν3.29 × 1015s−1=µ1n21−1n22¶1n22=1n21−ν3.29 × 1015s−1=14−6.909 × 1014s−13.29 × 1015s−1= 0.04n22=10.04n2= 5OneD Ground State08:06, general, multiple choice, < 1 min, fixed.004 (part 1 of 1) 6 pointsIf a particle is in a one-dimensional box and isin its ground state, where would you MOSTprobably find the particle?1. in the center of the box correct2. at the two ends of the box3. either side of the center of the box4. anywhere in the boxExplanation:ChemPrin3e T01 7808:03, general, multiple choice, < 1 min, fixed.005 (part 1 of 1) 6 pointsEstimate the minimum uncertainty in the po-sition of an electron of mass 9.109 × 10−31kgif the error in its speed is 300000 m/s.1. 386 pm2. 386 × 10−12m3. 193 pm correct4. 1.93 × 10−12mExplanation:m = 9.109 × 10−31kg ∆v = ±300000 m/s∆x =¯h2 m ∆v=1.055 × 10−34J · s2 (9.109 × 10−31kg) (300000 m/s)= (1.93033 × 10−10m)µ1012pm1 m¶= 193.033 pm .DeBroglie Wavelength 0308:03, general, multiple choice, < 1 min, fixed.006 (part 1 of 1) 6 pointsWhat is the de Broglie wavelength ofSchrodinger’s cat, Albert, running to his foodbowl. Albert has a mass of 5200 g and isrunning at 1.6 m/s.1. 7.964 × 10−35m correct2. 7.964 × 10−38m3. 4.978 × 10−35m4. 5.513 × 10−33mExplanation:λ =hp=hm · v=6.626 × 10−34kg·m2s(5.2 kg) (1.6 m/s)= 7.96394 × 10−35mVersion 001 – Exam 1 – David Laude (54705) 4Schrodinger Eq 0108:06, general, multiple choice, < 1 min, fixed.007 (part 1 of 1) 6 pointsWhich of the following applications of theSchrodinger equation includes a potential en-ergy term with both attractive and repulsiveterms?1. V (r) for electrons in the helium atomcorrect2. V (x) for a particle in a box3. V (r) for the electron in the hydrogenatom4. V (x) for the standing wave of a pluckedguitar string5. None of theseExplanation:ChemPrin3e T01 3808:07, general, multiple choice, < 1 min, fixed.008 (part 1 of 1) 6 pointsThe three quantum numbers for an electron ina hydrogen atom in a certain state are n = 4,` = 1, m`= 1. The electron is located inwhat type of orbital?1. 4s2. 3p3. 3d4. 4d5. 4p correctExplanation:The notation is n`, wheren = 1, 2, 3, 4, 5, ..., ` = 0, 1, 2, ..., (n − 1)represented as a letter: ` = 0 → s, ` = 1 → p,` = 2 → d, ` = 3 → f, ` = 4 → g, ` =5 → h, etc, and m`= −`, −(` − 1), −(` −2), ..., 0, ..., +(` − 2), +(` − 1), `.The value of m`is not needed to determinethe orbital type, as long as it is valid.Quantum Number 0108:08, general, multiple choice, < 1 min, fixed.009 (part 1 of 1) 6 pointsWhat is the total number of orbitals found inthe n = 1 through n = 4 shells?1. 30 correct2. 163. 604. 105. None of theseExplanation:Degenerate Energy Levels08:12, general, multiple choice, < 1 min, fixed.010 (part 1 of 1) 6 pointsWhich of the subshells possess degenerate en-ergy levels?1. All except …
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