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UT CH 301 - Exam 2

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001version last name first name signatureBIBERDORF CH301unique: 48815, 48830Exam 2Fall 2019Oct 9, 2019Wed 5:30pm - 7pmRemember to refer to the Periodic Table handout that is separate from this exam copy.NOTE: Please keep this exam copy intact (all pages still stapled - including this cover page). Youmust turn in ALL the mat erials that were distributed. This means that you turn in yourexam copy (name and signature included), bubble sheet, free response (name and versionnumber included), periodic table handout, and all scratch paper. Please also have yourUT I D card ready to show as well.Version 001 – Exam 2 - F19 – biberdorf – (48815) 2This print-out should have 16 questions.Multiple-choice questions may continue onthe next column or page – find all choicesbefore answering.001 10.0 pointsUltraviolet light from the sun that falls inthe range of 290 to 320 nm (known as UVB)can cause skin cancer in humans. What is thefrequency of a UVB photon with a wavelengthof 290 nm?1. 1.10 × 1015s−12. 1.23 × 1015s−13. 9.68 × 1014s−14. 1.03 × 1015s−15. 9.45 × 1014s−1002 10.0 pointsA typical TV remote sends an infrared signalwith a frequency of 3.19 × 1014s−1. What isthe wavelength of the light?1. 1066 nm2. 957 nm3. 1180 nm4. 940 nm5. 1012 nm003 10.0 pointsHow did the Bohr model of the atom explainthe emission and absorption line spectra ofatoms?1. When atoms absorb photons the electronsspeed up in their orbits, and when atomsemit photons, the electrons sl ow down in theirorbits.2. Bohr’s model assigns a different colorto each electron in an at om, matching thecolor of that el ectro n’ s emission or absorptionline.3. Electron energies in an atom are lim-ited to certain specific va lues, which limitsthe photon energies that can be emitted orabsorbed.4. The Bohr model of the ato m could notexplain line spectra at all, and that’s whySchr¨odinger came up with the wave model5. The number of electrons in an atom corre-sponds to the number of lines in the emissionspectrum.004 10.0 pointsYour friend from OU attempted to determinethe el ectro n configuration for Neon and cameup with:1s22s12p7What do you tell him?1. This is incorrect; Pauli and Aufbau werenot obeyed.2. This is incorrect; Pauli and Hund’s werenot obeyed.3. This is incorrect; Hund’s and Aufbau werenot obeyed.4. This is incorrect; Aufbau was notobeyed.5. This is correct; Pauli, H und’s, and Aufbauwere ob eyed.6. This is incorrect; Pauli, Hund’s, and Auf-bau were not obeyed.005 10.0 pointsCan the Rydberg equation be used to accu-rately predict the wavelengths in the emissionspectrum for He+? Why or why not?1. No, the Rydberg equation can o nl y beused for hydrog en.Version 001 – Exam 2 - F19 – biberdorf – (48815) 32. Yes, the Rydberg equation works for allatoms listed on the current periodic table.3. Yes, the Rydberg equation can be usedfor systems that are i soelectronic with hydro-gen.4. No, the Rydberg equation can only beused for systems with one proton.006 10.0 pointsWhat is the electron configuration for Nb3+?1. [Kr] 5s24d32. [Kr] 5d23. [Kr] 5s24. [Kr] 4d25. [Kr] 4d36. [Kr] 5d3007 10.0 pointsConsider a radia l distribution plot that has alarge peak around 75 pm, a smaller peak at40 pm, and an even smal ler peak a t 1 5 pm.Given this i nformat ion, what does this radialdistribution plot correspond to?1. 2s2. 1p3. 3f4. 3s5. 3p6. 3d008 10.0 pointsAn amateur scientist builds a homemade pho-toelectric effect apparatus that uses a greenlaser pointer shining onto an aluminum platein a vacuum, but no electrons are ejected.Which of these actions is most likely to resultin electrons being ejected from the metal?1. Replace the green laser pointer with aninfrared TV remote cont rol.2. Use a lens to spread out the green laserlight over a wider area on the metal surface.3. Focus three green laser pointers on thesame spot on the metal.4. Replace the green laser pointer with ablue LED.5. Replace the green laser pointer with a redlaser pointer.009 10.0 pointsAn electron in a hydrogen atom falls to theground stat e and gives off a photon with anenergy of 1.94 × 10−18J. What energy leveldid the electron fall from?1. n = 12. n = 43. n = 54. n = 35. n = 2010 10.0 pointsWhich of the following sets of quantum num-bers is NOT valid?1. n = 3, ℓ = 1, mℓ= −1, ms= +122. n = 4, ℓ = 4, mℓ= −2, ms= +123. n = 1, ℓ = 0, mℓ= 0, ms= −124. n = 2, ℓ = 1, mℓ= 1, ms= +125. n = 4, ℓ = 3, mℓ= 3, ms= −12011 10.0 pointsVersion 001 – Exam 2 - F19 – biberdorf – (48815) 4Rank the following atoms in order of increas-ing effective nuclear charge: fluorine, arsenic,sulfur.1. fluorine < arsenic < sulfur2. arsenic < fluorine < sulfur3. arsenic = sulfur < fluorine4. fluorine < sulfur < arsenic5. fluorine < sulfur = arsenic6. arsenic < sulfur < fluorine012 10.0 pointsIdentify the element with the following elec-tron configuration:[Xe] 6s24f145d61. Rhodium (Rh)2. Molybdenum (Mo)3. Ruthenium (Ru)4. Iridium (Ir)5. Tungsten (W)6. Osmium (Os)013 10.0 pointsSchr¨odinger’s wave model of the atom is basedon a complex mat hematical equation whosesolutions yield wavefunctions and energies.What do the wavefunctions tell us?1. the n values for the Rydberg equation2. the regions in space around the nucleuswhere the electron is most likely to be found3. the possible wavelengths of the electron4. the wavelengths in the visible emissionspectrum for hydrogen5. the energy that an electron must have inorder to be found in a given orbital014 10.0 pointsSelect the correct statement(s) that describea neutral element that has the following q uan-tum numbers for its last filled electron whenin the ground state:n = 4 , ℓ = 2, mℓ= −1, ms= +12I. This element is a transit ion meta l.II. This element would al so have electrons inthe n = 5 energy level.III. There are 18 inner-shell electrons.1. I and III only2. I, I I, and III3. II only4. III only5. I only6. I and II only7. II and III only015 10.0 pointsIf 258 nm of light is shined onto a lithiumsurface in a vacuum, how much kineti c energywill the ejected electrons have? The workfunction for lithium is 2.93 eV.1. 3 .00 × 10−19J2. 2 .85 × 10−19J3. 3 .37 × 10−19J4. 2 .66 × 10−19J5. 3 .25 × 10−19J016 10.0 pointsVersion 001 – Exam 2 - F19 – biberdorf – (48815) 5Copper, silver, and gold have electron config-urations that do not follow the Aufbau prin-ciple. Ba sed on this k nowledge, whi ch of thefollowing lanthanides would you also expectto disobey the Aufbau


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