Anna$Audler$Stats$10:$Section$3A$UID:$304295761$TA:$Luis$Sosa$Homework$#2$$3.3:$The$typical$age$of$the$CEOs$is$56L60.$The$distribution$is$symmetric,$so$the$value$in$the$middle$should$be$the$mean$$3.4:$The$approximate$mean$number$of$siblings$is$2.$The$distribution$is$right$skewed,$so$the$mean$should$be$towards$the$left$side$of$the$graph.$$3.6:$A)$Mean$=$2.8;$The$first$6$first$ladies$on$average$had$around$2L3$children,$however,$the$mean$is$effected$by$outliers$as$2$first$ladies$had$0$children$and$2$ladies$had$5$or$more$children.$B)$The$mean$for$the$first$ladies$was$lower$than$that$of$the$average$woman$during$the$1800s$C)$Martha$Jefferson$is$farthest$from$the$mean$(6)$and$contributes$most$to$the$standard$deviation$D)$SD$=$2.6$$3.10:$A)$The$mean$population$of$states$east$of$the$Mississippi$River$is$6871.22$thousand$people$and$the$mean$of$the$states$west$of$the$river$is$5323.13$thousand$people,$showing$that$the$eastern$states$tend$to$have$the$larger$populations.$B)$The$standard$deviations$of$the$states$east$of$the$Mississippi$River$is$5135.49$thousand$people,$and$the$standard$deviation$of$ t he$states$west$of$the$river$is$8287.38$people,$showing$that$western$states$tend$to$have$more$variation$in$terms$of$population.$$3.14:$Group$A$because$there$is$greater$variation$from$the$mean$in$the$middle$compared$to$group$b$where$the$data$tends$to$be$more$grouped$up$near$the$mean.$$3.15:$A)$Top:$3462+500=3962;$Bottom:$3462L500=2962$B)$Yes,$the$birth$weight$of$2800$is$more$than$one$standard$deviation$below$the$mean$since$it$is$less$than$2962$$3.17:$A)$SD=1.4$years$B)$The$same.$The$SD$in$20$years$will$remain$1.4.$SD$does$not$depend$on$the$size$of$the$number,$just$how$far$apart$the$numbers$are$from$each$other$C)$3$years$D)$Larger:$mean$is$23$years.$When$20$is$added$to$each$number,$the$mean$would$also$increase$by$20$$$3.22:$$A)$Between$23$and$795$B)$Between$216$and$602$C)$Although$896$crimes$per$100,000$is$much$greater$than$the$mean,$it$lies$within$3$standard$deviations$where$99.7%$of$data$lies,$so$it’s$not$extremely$unusual.$D)$It$would$not$be$unusual$because$a$crime$rate$of$503$is$within$one$deviation$from$the$mean.$$3.23:$z$=$$€ 4060 − 3331729$=$1$A)$68%$because$of$the$empirical$rule$B)$95%$because$of$the$empirical$rule$C)$Nearly$all$of$the$data$should$be$w
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