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Mizzou CHEM 1320 - Chemical Equations
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CHEM 1320 1st Edition Lecture 5Outline of Last Lecture I. Periodic TableII. Ions III. Molecules IV. Ionic CompoundsV. Molecular CompoundsVI. ElementsOutline of Current Lecture I. Chemical EquationsII. Balancing Chemical EquationsCurrent LectureI. Chemical EquationsLavoisier means mass conserved in a chemical reaction. These chemical reactions are expressed in a chemical reaction. There are two parts to every equation; reactants and products. The law of conservation of mass states that matter cannot be lost in a chemical reaction. II. Balancing Chemical Equations Stoichiometry is the conservation of mass. There are three steps in balancing chemical reactions. 1). Translate the words in the reaction and product.2). Balance the elements that appear once and then the remaining elements.3). Check to make sure the numbers are equal on both sides.Example:C+O2  CO is the original equation that needs to be balanced. 2C+O2  2CO would be the balanced equationThese notes represent a detailed interpretation of the professor’s lecture. GradeBuddy is best used as a supplement to your own notes, not as a substitute.- Since the oxygen atom has a 2 you need to put a 2 on the opposite side. Putting the 2 in front of the CO makes both those atoms have 2. Then since carbon now has 2, you needto balance the other side by adding another 2 before the carbon. More Examples:NH4NO3  N2O + H2OBalances to be: NH4NO3  N2O + 2H2O (putting a 2 before the H2O balances the equation)Be2C + H2O  Be(OH)2 + CH4Balances to be: Be2C + 2H2O  2Be(OH)2 +


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Mizzou CHEM 1320 - Chemical Equations

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