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WVU PHYS 102 - Total Internal Reflection
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PHYS 101 1st Edition Lecture 27 Outline of Last Lecture I. Electromagnetic Waves continued…II. Deriving Refractive Index III. Practice Problems Outline of Current Lecture IV. Total Internal ReflectionV. Practice ProblemsCurrent Lecture IV. Total Internal ReflectionTest 3: Coming up on Monday (11/10)! -Chapter 21 few sections & Chapter 22 - Come to class & study 4 times to get over 100Chapter 22 equations: - n1sin1 = n2sin2- n = c/v Chapter 21 equations: -  = c/f for vac/air ;  = v/f for material - E = hf Total internal reflection: when a wave cannot pass through to Medium 2 & is entirely reflected back to Medium 1 Two conditions: 1) Medium 2 is of lower refractive index (n) than that of Medium1 2) The incident angle is greater than a critical angle Up to today: low n  high n These notes represent a detailed interpretation of the professor’s lecture. GradeBuddy is best used as a supplement to your own notes, not as a substitute.Air  glass V. Practice Problems A. n1sin1 = n2sin21 sin (30) = 1.4 sin20.5 = 1.4 sin2sin2 = 0.5/1.4 2 = sin-1(0.5/1.4)= 21.9 less than 30 ; no total internal reflectionNow: n1 is greater than n2Glass to air Diamond to air n1sin1 = n2sin2diamond air2.419 sin (20) = 1 sin 2 2 = 55.83 > 1n1sin1 = n2sin2diamond air 2.419 sin (30) = 1 sin 2 2 = 70.9If we increase 1 more until 2 = 90B. What is the critical angle of Diamond? You say 2 = 90. n1sin1 = n2sin22.419 sin c = (1) sin (90)2.419 sin c = 1sin c = 1/2.419 c = sin-1(1/2.419)c = 24.3if 1 > 24.3, 2 will be greater than


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WVU PHYS 102 - Total Internal Reflection

Type: Lecture Note
Pages: 3
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