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WVU PHYS 102 - Snell's Law
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PHYS 101 1st Edition Lecture 28Outline of Last Lecture I. Total Internal ReflectionII. Practice ProblemsOutline of Current Lecture III. Snell’s Law Continued…IV. Practice ProblemsCurrent Lecture III. Snell’s Law Continued…A. air (n=1)quartz (n=1.458)Diamond is more beautiful because light gets trapped. tan 2 = d/hh= d/tan 2h= 0.06/ tan 2  get 2 & the problem is solved. & the speed of the wave is 10% lower in the liver than medium; vmed=100, vliver= 90 n1 sin 1 = n2 sin 2nmed sin(50) = n2 sin 2sin 2 = (nmed/nliver)sin(50)sin 2 = [(c/vmed)/(c/vliver)]sin(50)  c= spread of ultrasonic in air (don’t know what it is)sin 2 = (vliver/vmed) sin(50)  where Vliver is 10% less sin 2 = 0.9 sin (50) = sin-1(0.689)These notes represent a detailed interpretation of the professor’s lecture. GradeBuddy is best used as a supplement to your own notes, not as a substitute.2 = 43.6h = c/v  h= (0.6/ tan 2) = 0.6/ tan(43.6) = 0.063 m or 6.3 cm IV. Practice Problems A. E = hf=(6.63 X 10-14)f=(6.63 X 10-14)(c/)=(6.63 X 10-14)(3 X 106/1 X 10-10)E = 1.99 X 10-15 J for 1 photon = ? in eV (electron Volts) eV = the unit of energy (E/e) = 1.99 X 10-15/1.6 X 10-14 = 12.4


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WVU PHYS 102 - Snell's Law

Type: Lecture Note
Pages: 2
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