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WVU PHYS 102 - Calculating Coulomb's Force
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PHYS 102 1nd Edition Lecture 4 Outline of Last Lecture I. The Electric FieldII. Electric Field Lines Outline of Current Lecture III. Calculating Coulomb ForceCurrent LectureIII. Calculating Coulomb Force A. pg. 542 #10 Calculate the magnitude and direction of the Coulomb force on each of the three charges shown in Figure 15.10. r1= 3.00 cm, r2= 2.00 cm, q1= 6.00 C, q2=1.50 C, q3= -2.00 C= 10-6 Net force on q1F1 = k[(q1 X q2)/(r2)] = (9 X 109)[(6 X 10-6)(1.5 X 10-6)/ (3/100)2] = 89.9 Newtons or (89.9 N)(1 pound / 4.5 N) = 20 pounds F2 = k[(q1 X q2)/(r2)]= (9 X 109)[(6 X 10-6)(-2 X 10-6)/(5/100)2] = 43.2 Newtons q1Fnet= ? = 89.9 – 43.2 = 46.7 Newtons (magnitude) These notes represent a detailed interpretation of the professor’s lecture. GradeBuddy is best used as a supplement to your own notes, not as a substitute.The direction of this force is to the left. Net force on q2:F3 = k[(q1 X q2)/(r2)]= (9 X 109)[(1.5 X 106)(-2 X 10-6)]/(2/100)2= 67.4 N Fnet magnitude= 89.9 + 67.4 = 157 NewtonsThe direction of this force is to the right. Net force on q3: Fnet magnitude = 43.2 + 67.4 = 111 NewtonsThe direction of this force is to the


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WVU PHYS 102 - Calculating Coulomb's Force

Type: Lecture Note
Pages: 2
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